Answer:
2x^2 + 2y^2 + 2z^2
Step-by-step explanation:
x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2
First step is to put all the same ones together
( FYI, xy and yx is the same thing, just like how
2 x 3 and 3 x 2 is the same thing) this time I'll bracket the groups to make it easier on the eyes
(x^2 +x^2) + (xy - xy) +( y^2 + y^2) + (yz - yz) +
(z^2 +z^2) + (zx - zx)
2x^2 + 2y^2 + 2z^2
All the others just cancel themselves out, for example, xy-xy
When anything minus themselves it will become 0
First we have to work out everything inside the parentheses (according to PEMDAS):
9 × 2 = 18
4 - 2 = 2
Now, we can rewrite the expression:
4 + 18 ÷ 2 + 1
According to PEMDAS, we should complete the division in the middle first:
18 ÷ 2 = 9
Now we can rewrite the expression again:
4 + 9 + 1
And now it's as simple as just adding the three numbers together:
4 + 9 + 1 = 14
Your final answer is 14. :)
Answer:
It's 4x - 8 + 4y
Step-by-step explanation:
4(x-2+y)
4 (x) = 4x
4 (2) = 8
4 (y) = 4y
4x - 8 + 4y
