Answers:
In these exercices are ilustrated the representations of the fractions
2) Firstly, we have 3 equal segments, each one representing 
, hence:
is <u>3</u> copies of
Let's prove it, taking into account we are adding fractions with the same denominator:
There are <u>4</u> equal parts that make a whole
Four copies of <u></u> make 
or <u>1</u> whole
3) Here we have a line divided into four segments, each one of 
. Hence:
This is 
of a line. is <u>4</u> lengths of
If we draw one more we will have 
or 1 whole.
Then:
<u>5</u> lengths of make or <u>1</u> whole.
4) In this part the answer is in the attached image. If we have two equal segments, each one of 
we will have as a result 
.
If we add another segment, we will have three segments of , having as a result 
I think the correct answer is A. Hope this helps.
The answer is c hope this helped
Answer:
-1, 2, 6
Step-by-step explanation:
We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).
Now, we have, 
⇒
⇒
⇒
⇒![(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0](https://tex.z-dn.net/?f=%28x-2%29%28x-6%29%5B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20-5x-2%7D%20-%5Cfrac%7B1%7D%7B4%7D%20%5D%3D0)
⇒ 
or, ![[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20-5x-2%7D%20-%5Cfrac%7B1%7D%7B4%7D%20%5D%3D0)
If, (x-2)(x-6) =0, then x=2 or x=6
If, , then 
and (x-6)(x+1) =0
Therefore, x=6 or -1
So the solutions for x are -1, 2 6. (Answer)
