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o-na [289]
3 years ago
11

Write the equation of a line that goes through the points (-7,10) and (1,4)

Mathematics
2 answers:
Bad White [126]3 years ago
8 0
I’m pretty sure the answer is y=3/4x-13/4
Len [333]3 years ago
6 0

acb

Step-by-step explanation:

i took test

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The width of a model train’s car measures 2.4 in. The scale is 1:56. What is the width of the actual train car to the nearest fo
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Answer:

11.2 feet

Step-by-step explanation:

7 0
4 years ago
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Sally has 13 baseball cards in each week her grandpa bring 7 more sally created this equation y=7x +13 use the equation to answe
fiasKO [112]

Answer:

13 means the starting number

13 is the y-intercept (0,13)

5 0
3 years ago
does anyone understand this or can anyone explain what i need to do please ?? there’s no instructions
Contact [7]

Answer:

nah man... good luck tho

3 0
3 years ago
PLEASEE HELP WITH THIS IMAGE!! WILL GIVE BRAINLIEST!!!!
kotykmax [81]

Step-by-step explanation:

area of the triangle

1/2xbxh

1/2(12x9)

1/2(108)

area of triangle is 54in²

area of rectangle

2(L+W)

2(15+6)

2(21)

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3 0
3 years ago
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Find the values of c such that the area of the region bounded by the parabolas
evablogger [386]
For there to be a region bounded by the two parabolas, you first need to find some conditions on c. The two parabolas must intersect each other twice, so you need two solutions to

16x^2-c^2=c^2-16x^2

You have

32x^2=2c^2\implies 16x^2=c^2\implies x=\pm\dfrac{|c|}4

which means you only need to require that c\neq0. With that, the area of any such bounded region would be given by the integral

\displaystyle\int_{-4|c|}^{4|c|}\bigg((c^2-16x^2)-(16x^2-c^2)\bigg)\,\mathrm dx

since c^2-16x^2>16x^2-c^2 for all c\neq0. Now,

\displaystyle\int_{-|c|/4}^{|c|/4}\bigg((c^2-16x^2)-(16x^2-c^2)\bigg)\,\mathrm dx=2\int_0^{|c|/4}(2c^2-32x^2)\,\mathrm dx

by symmetry across the y-axis. Integrating yields

\displaystyle2\int_0^{|c|/4}(2c^2-32x^2)\,\mathrm dx=4\int_0^{|c|/4}(c^2-16x^2)\,\mathrm dx
=4\left[c^2x-\dfrac{16}3x^3\right]_{x=0}^{x=|c|/4}
=c^2|c|-\dfrac{|c|^3}3
=\dfrac{2|c|c^2}3=144
|c|c^2=216

Since 216=6^3, you have c=\pm6.
3 0
3 years ago
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