Question

How do I answer this question :)))

Answer 1

Answer:

The first triangle.

Step-by-step explanation:

The sides LM, MN, and LN of  Δ LMN have sides of lengths 15√2, 15 and 15 respectively.

Now, in the first graph, the sides of the graphed triangle are 3√2, 3 and 3 respectively.

So, the ratio of the corresponding sides is $\frac{15\sqrt{2} }{3\sqrt{2} } = \frac{15}{3} = \frac{15}{3} = 5$  

Therefore, the first graphed triangle is similar to Δ LMN using the SSS similarity theorem. (Answer)