Question

What are the roots of the function f(x)=x^2+x-6

Answer 1

For this case we have the following quadratic function:

$f (x) = x ^ 2 + x-6$

We must find its roots. We can factor, looking for two numbers that when added to +1 and multiplied by -6. These are:

+3 and -2

$+ 3-2 = 1\\(+3) * (- 2) = - 6$

Then, the factored form is:

$(x + 3) (x-2) = 0$

So, the roots are:

$x_ {1} = - 3\\x_ {2} = 2$

Answer:

$x_ {1} = - 3\\x_ {2} = 2$

Answer 2

Answer:

None of the above

Step-by-step explanation:

A is the closest but it should be 2 and -3