All categories

3 years ago

What is 3÷4×9+9-4+59÷23

Mathematics

2 answers:

4vir4ik [10]3 years ago

7 0

Answer:

1317/92

Step-by-step explanation:

brainlest plz

Sindrei [870]3 years ago

4 0

Answer:

14.3152173913

Step-by-step explanation:

You might be interested in

At your first wedding event, you sold 240 To

astraxan [27]

Answer:

1.5%

Step-by-step explanation:

240=100

40=*

40 over 240 multiplied by 100%

8 0

4 years ago

Read 2 more answers

If angle X has a measure of 40 degrees and angle Y is vertical to angle X what is the measure of angle Y?

erica [24]

If an angle is 70 degrees and there is an angle vertical to it, then that other angle also equals 70 degrees. Therefore, if angle X equals 40 degrees, then angle Y also equals 40 degrees. Hope this helps.

6 0

4 years ago

Read 2 more answers

Central limit theorem: Sample proportion

marysya [2.9K]

Answers wiebsuwbsyjwvs he dustbdysfais he eibssavabsbsusv god blesses you

8 0

3 years ago

If the graph of the function f (X) is represented in the attached figure, which of the graphs presented in the options represent

Ahat [919]

Answer:

A. g(x) = 1/3x + 1

Step-by-step explanation:

The line has points:

(0, -3) and (1, 0)

It has y-intercept b = -3 and a slope:

m = (0 + 3)/1 = 3

The equation:

f(x) = 3x - 3

It inverse is (let's call it g(x)):

x = 3y - 3
3y = x + 3
y = 1/3x + 1
g(x) = 1/3x + 1

The slope of the inverse function is 1/3 and the y-intercept is 1

The graph reflecting this is A

6 0

3 years ago

Read 2 more answers

How do I determine z ∈ C:

saw5 [17]

Simplify the coefficient of z on the left side. We do this by rationalizing the denominators and multiplying them by their complex conjugates:

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3-2i}{1+i}\cdot\dfrac{1-i}{1-i} - \dfrac{5+3i}{1+2i}\cdot\dfrac{1-2i}{1-2i}$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{(3-2i)(1-i)}{1-i^2} - \dfrac{(5+3i)(1-2i)}{1-(2i)^2}$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3 - 2i - 3i + 2i^2}{1-(-1)} - \dfrac{5 + 3i - 10i - 6i^2}{1-4(-1)}$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{3 - 5i + 2(-1)}2 - \dfrac{5 - 7i - 6(-1)}5$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{1 - 5i}2 - \dfrac{11 - 7i}5$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{1 - 5i}2\cdot\dfrac55 - \dfrac{11 - 7i}5\cdot\dfrac22$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = \dfrac{5 - 25i - 22 + 14i}{10}$

$\dfrac{3-2i}{1+i} - \dfrac{5+3i}{1+2i} = -\dfrac{17 + 11i}{10}$

So, the equation is simplified to

$-\dfrac{17+11i}{10} z = \dfrac12 - \dfrac{2i}5$

Let's combine the fractions on the right side:

$\dfrac12 - \dfrac{2i}5 = \dfrac12\cdot\dfrac55 - \dfrac{2i}5\cdot\dfrac22$

$\dfrac12 - \dfrac{2i}5 = \dfrac{5-4i}{10}$

Then

$-\dfrac{17+11i}{10} z = \dfrac{5-4i}{10}$

reduces to

$-(17+11i) z = 5-4i$

Multiply both sides by -1/(17 + 11i) :

$\dfrac{-(17+11i)}{-(17+11i)} z = \dfrac{5-4i}{-(17+11i)}$

$z = -\dfrac{5-4i}{17+11i}$

Finally, simplify the right side:

$-\dfrac{5-4i}{17+11i} = -\dfrac{5-4i}{17+11i} \cdot \dfrac{17-11i}{17-11i}$

$-\dfrac{5-4i}{17+11i} = -\dfrac{(5-4i)(17-11i)}{17^2-(11i)^2}$

$-\dfrac{5-4i}{17+11i} = -\dfrac{85 - 68i - 55i + 44i^2}{289-121(-1)}$

$-\dfrac{5-4i}{17+11i} = -\dfrac{85 - 68i - 55i + 44(-1)}{410}$

$-\dfrac{5-4i}{17+11i} = -\dfrac{41 - 123i}{410}$

$-\dfrac{5-4i}{17+11i} = -\dfrac{41 - 41\cdot3i}{410}$

$-\dfrac{5-4i}{17+11i} = -\dfrac{1 - 3i}{10}$

So, the solution to the equation is

$z = -\dfrac{1-3i}{10} = \boxed{-\dfrac1{10} + \dfrac3{10}i}$

4 0

3 years ago