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Zina [86]
3 years ago
10

What is 3÷4×9+9-4+59÷23

Mathematics
2 answers:
4vir4ik [10]3 years ago
7 0

Answer:

1317/92

Step-by-step explanation:

brainlest plz

Sindrei [870]3 years ago
4 0

Answer:

14.3152173913

Step-by-step explanation:

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Which of the following equations have the same solution? Give reasons for your answer that do not depend on solving the equation
topjm [15]

<u>Answer:</u>

A,C and E are equal with 4 as their solution; F and B are equal with 0 as their solution. D is independent.

<u>Solution:</u>

A. -(7-4x)=9

Taking off the brackets we get,

-7+4x=9 \Rightarrow +4x=9+7

\Rightarrow 4x=16 \\

\Rightarrow x=\frac{16}{4} \Rightarrow 4

Here x=4 --- (a)

B. 12=-4(-6x-3)

Multiplying -4 inside we get,

12=+24x+12 \Rightarrow 12-12=24x

\Rightarrow x=0

Here x=0 --- (b)

C. 5x+34=-2(1-7x)

Multiplying -2 inside we get,

5x+34=-2+14x

Grouping the terms,

34+2=14x-5x \Rightarrow 36=9x

\Rightarrow x=4

Here x=4 --- (c)

D. 14=-(x-8)

\Rightarrow 14=-x+8 \Rightarrow -x=14-8

\Rightarrow x=-6

Here x=-6 --- (d)

E. -8=-(x+4)

\Rightarrow -8=-x-4 \Rightarrow x=8-4

\Rightarrow x=4

Here x=4 --- (e)

F. x+5=-5x+5

\Rightarrow x+5x=5-5

6x=0 \Rightarrow x=0

Here x=0 --- (f)

So, from the above calculations we can conclude that (a), (c) and (e) are equal and (f) and (b) are equal but (d) is independent because it has a different solution.

5 0
4 years ago
Given the following number line, select all of the true statements.​
IRINA_888 [86]

Answer: a<c

| a | > | b |

Step-by-step explanation:

7 0
3 years ago
on monday sheila sold 20 apples, on tuesday she sold 12 apples, on wednesday she sold 20 apples, and on thursday she sold 28 app
zimovet [89]

1, she picks about 20+12+(20+28)=32+48=80.

5 0
4 years ago
Read 2 more answers
Please need help asap!!
vagabundo [1.1K]

a+b+c=180,  \text{ }c+e=180 \implies \\ a+b+c=c+e \implies \\ a+b=e\\

This result is actually true for any exterior angle. The exterior angle of a triangle is equal to the sum of the two remote angles, and above is a short proof of it.

6 0
4 years ago
Please SHOW WORK, will mark brainlist if correct
riadik2000 [5.3K]

Answer:

\huge\boxed{\sf \frac{x+3}{x-3}}

Step-by-step explanation:

\displaystyle = \frac{x+7}{x^2+4x-21} \div \frac{x+5}{x^2+8x+15} \\\\Apply \ mid-term \ break\\\\= \frac{x+7}{x^2 +7x-3x-21} \div \frac{x+5}{x^2 +3x+5x+15} \\\\= \frac{x+7}{x(x+7)-3(x+7)} \div \frac{x+5}{x(x+3)+5(x+3)} \\\\Taking \ (x+3) \ and \ (x+7) \ common\\\\= \frac{x+7}{(x-3)(x+7)} \div \frac{x+5}{(x+3)(x+5)} \\\\= \frac{1}{x-3} \div \frac{1}{x+3} \\\\= \frac{1}{x-3} * (x+3)\\\\= \frac{x+3}{x-3} \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
5 0
3 years ago
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