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2 years ago

If possible please help! With 12

Mathematics

2 answers:

madreJ [45]2 years ago

6 0

Answer:

Step-by-step explanation:

y = 1y

1y+0.4y =1.4y

Irina18 [472]2 years ago

5 0

Answer:

b. (1.4y)

Step-by-step explanation:

When a variable has no number next to it, it is always going to be 1 multiplied by the variable. adding 1y and 0.4y would make 1.4y.

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Find the greatest common monomial factor : 4a^5b^2 and ab

3241004551 [841]

4a^5b^2=2*2*a*a*a*a*a*b*b
ab=a*b
greatest factor is ab

8 0

2 years ago

What is the equation for the hyperbola shown?

castortr0y [4]

Answer:

$\frac{x^{2} }{3600} - \frac{y^{2} }{121} = 1$

Step-by-step explanation:

Since the hyperbola opens left and right with a center at the origin, then

$\frac{x^{2} }{^{2} } - \frac{y^{2} }{b^{2} } = 1$

In the graph a = 60 and b = 11

$\frac{x^{2} }{60^{2} } - \frac{y^{2} }{11^{2} } = 1$ .

$\frac{x^{2} }{3600} - \frac{y^{2} }{121} = 1$

7 0

2 years ago

Explain how to make a precise graph of y = -2x + 3 without making a T-Table.

kifflom [539]

Answer:

x 2 + 5 x + 6

Step-by-step explanation:

y = m x + c

y- intercept

x = 0

y = (-2) (0) + 3

(x =0, y = 3)

<h3>slope -2 </h3><h3>y = -1 x + 3</h3>

8 0

2 years ago

If the geometric mean of a and 34 is 6 sqrt(17) find the value of a

Alborosie

Using the geometric mean concept, it is found that the value of a is 18.

----------------------

The geometric mean, of a data-set of n elements, $(n_1, n_2, ..., n_n)$ , is given by:

$G = \sqrt[n]{n_1 \times n_2 \times ... \times n_n}$

That is, the nth root of the multiplication of all elements.

----------------------

In this question:

Two elements(n = 2), a and 34.
$G = 6\sqrt{17}$

Thus:

$\sqrt{34a} = 6\sqrt{17}$

We find the square of each side, so:

$(\sqrt{34a})^2 = (6\sqrt{17})^2$

$34a = 36\times17$

Simplifying both sides by 17:

$2a = 36$

$a = \frac{36}{2}$

$a = 18$

The value of a is 18.

A similar example is given at brainly.com/question/15010240

3 0

3 years ago

Answer my question please help

Alchen [17]

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I ᕼOᑭᗴ IT ᕼᗴᒪᑭՏ

ǝɹnsʇouɯᴉ#

6 0

3 years ago