The likelihood that the first two offspring of the cross will have congenital analgesia would be 1/16
<h2>Autosomal Recessive Traits</h2>
For autosomal recessive traits, two recessive alleles are needed for the trait to manifest while one recessive allele means heterozygosity.
In this case, let us assume that congenital analgesia is represented by the allele b; heterozygous individuals will, thus, be Bb.
Bb x Bb
BB Bb Bb bb
Probability of producing unaffected offspring = 3/4
Probability of producing affected offspring = 1/4
Likelihood of the first two offspring having congenital analgesia = probability of first having congenital analgesia and the second having congenital analgesia
= 1/4 x 1/4
= 1/16
More on genetical probabilities can be found here: brainly.com/question/851793?referrer=searchResults
<span>B. converted from nucleic acids to amino acids in the nucleolus.
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Answer:
UAGCAGUUAGUUUU
Explanation:
The sequence matches up with the corresponding bases. Because it is RNA A goes with U not T but T still goes with A.
A T
U A
Answer:
true
Explanation:
In the nucleus of each cell, the DNA molecule is packaged into thread-like structures called chromosomes. Each chromosome is made up of DNA tightly coiled many times around proteins called histones that support its structure.
Answer:
Throat infection turns into Tuberculosis.
Explanation:
A small infection can be changed into a big disease if it can't be controlled through medication and treatment. For example, at first coughing occurs due to throat infection but increase its intensity leads to more damaged to the throat which leads to the Tuberculosis disease. So this means that if the duration of a small disease increases, it turns into a big problem.