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2 years ago

Explain fully, in your own words, why the temperature during PCR goes through cycles of 94C, 50C, 72C.

Physics

1 answer:

Aliun [14]2 years ago

3 0

Answer:

Explanation:

The DNA polymerase used in PCR reaction usually can tolerate high temperature (94degree celcius), the temperature necessary to separate two complementary strands of DNA in a test tube.

If PCR goes through 72degree celcius, which is the temperature optimum for taq polymerase. It starts the extension process where taq polymerase will work away from the primer provided and generated a new DNA strand.

If PCR goes through 50degree celcius, it is annealing temperature. It is related to the melting temperature of the primers and must be determined for each primer pair used in PCR.

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As part of an interview for a summer job with the Coast Guard, you are asked to help determine the search area for two sunken sh

MrMuchimi

Answer: $37^{\circ}$ North of west

Explanation:

Given

40,000-ton luxury line traveling 20 knots towards west and

60,000 ton freighter traveling towards North with 10 knots

suppose v is the common velocity after collision

conserving momentum in west direction

$20\times 40,000=(20,000+60,000)v\cos \theta$

suppose the final velocity makes \theta angle with x axis

$v\cos \theta =10----1$

Conserving Momentum in North direction

$10\times 60,000=80,000\times v\sin\theta$

$v\sin \theta =\frac{15}{2}----2$

divide 1 and 2

$\tan \theta =\frac{3}{4}$

$\theta =37^{\circ}$

so search in the area $37^{\circ}$ North of west to find the ship

3 0

2 years ago

Please answer these questions 30 points

Maksim231197 [3]

Answer:

if i were you i would try to do the work because if you let someone else you wont be able to understand the question

6 0

2 years ago

Read 2 more answers

The battleship and enemy ships 1 and 2 lie along a straight line. Neglect air friction. battleship 1 2 Consider the motion of th

DaniilM [7]

Answer:

$\frac{t_1}{t_2} = \frac{sin\theta_1}{sin\theta_2}$

Explanation:

The vertical component of the initial velocities are

$v_v = v_0sin\theta$

If we ignore air resistance, and let g = -9.81 m/s2. The the time it takes for the projectiles to travel, vertically speaking, can be calculated in the following motion equation

$v_vt - gt^2/2 = s = 0$