Answer:
The measure of the third arc is 
Step-by-step explanation:
step 1
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
in this problem
Let
x----> the greater arc of the circle intercepted by the secant and the tangent
y----> the smaller arc of the circle intercepted by the secant and the tangent
----> equation A
-----> equation B
Substitute equation B in equation A and solve for y
Find the value of x
step 2
Find the measure of the third arc
Let
z------> the measure of the third arc
we know that
-----> complete circle
substitute the values and solve for z
Answer: sin
= ± 
Step-by-step explanation:
We very well know that,
cos2A=1−2sin²A
⟹ sinA = ±
As required, set A = & cos a= 
,thus we get
sin =± 
∴ sin =±
= ±
since ,360° < <450°
,180° < <225°
Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.
hope it helped!
42 rhhrhjejrjfitkkrjrjrhrt
Y=2/x. this equation has degree -1 whereas linear functions have degree 1
y=6x²-7 is nonlinear as it is degree 2
The ilne paralell to x=something is x=something else (both are constants)
slope=rise/run
x=-3
it rises infiniley and runs 0 (goes left to right 0)
slope=infinity/0=undefined
the slope is undefined
paralell lines have same slope
so the slope of a paralell line is also undefined
