Question

Eyjafjallajökull is a volcano in Iceland. Ina research reuption a projectile is ejected with an initial velcony of 304 feet per second. The height H, in feet is given the equation H=16t^2 + 304t

Answer 1

Answer:

t = 9.5 seconds

Step-by-step explanation:

Given that,

The initial velocity of the projectile is 304 ft/s

The height of the projectile is given by :

$H=16t^2 + 304t$

For maximum height,

Put h' = 0

$h'=-32t+304$

or

$-32t+304=0\\\\t=\dfrac{304}{32}\\\\t=9.5 \ s$

So, the time taken to reach the maximum height is 9.5 seconds.