<h3><u>
Answer:</u></h3>
![\boxed{\boxed{\pink{\bf \leadsto Hence \ option\ [d]\ \bigg(y = \dfrac{5}{2}x + 5\bigg) \ is \ correct }}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Cpink%7B%5Cbf%20%5Cleadsto%20Hence%20%5C%20option%5C%20%5Bd%5D%5C%20%5Cbigg%28y%20%3D%20%20%5Cdfrac%7B5%7D%7B2%7Dx%20%2B%205%5Cbigg%29%20%5C%20is%20%5C%20correct%20%20%7D%7D%7D)
<h3>
<u>Step-by-step explanation:</u></h3>
Here from the given graph we can see that the graph the graph intersects x axis at (2,0) and y axis at (5,0). On seeing options it's clear that we have to use Slope intercept form . Which is :-
We know that slope is 
. So here slope will be ,
Hence the slope is 5/2 . And here value of c will be 5 since it cuts y axis at (5,0).
<h3>
<u>Hence</u><u> </u><u>option</u><u> </u><u>[</u><u> </u><u>d</u><u> </u><u>]</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u> </u><u>.</u><u> </u></h3>
Answer:
Now we can calculate the p value based on the alternative hypothesis with this probability:
The p value is very low compared to the significance level of 
then we can reject the null hypothesis and we can conclude that the true proportion of people liberal is higher than 0.24
Step-by-step explanation:
Information given
n=200 represent the random sample taken
X=75 represent the number of people Liberal
estimated proportion of people liberal
is the value that we want to test
z would represent the statistic
represent the p value
Hypothesis to test
We want to verify if the true proportion of adults liberal is higher than 0.24:
Null hypothesis:
Alternative hypothesis:
The statistic is given by:
(1)
Replacing the info given we got:
Now we can calculate the p value based on the alternative hypothesis with this probability:
The p value is very low compared to the significance level of then we can reject the null hypothesis and we can conclude that the true proportion of people liberal is higher than 0.24
Answer:
39
Step-by-step explanation:
Given the function :
h(t) = t² + 2
From t = 5 to t = 8
when, t = 5
h(5) = 5² + 2
h(5) = 25 + 2
h(t) at t = 5 ; equals 27
when, t = 8
h(5) = 8² + 2
h(5) = 64 + 2
h(t) at t = 8 ; equals 66
Net Change :
h(8). - h(5)
66 - 27 = 39
Answer:
C
Step-by-step explanation:
The rubber exercise ball is a sphere
the volume of a sphere= 4/3*pi*r3
where r = the radius of the sphere.
from the diagram, the radius = 4.5inches
Therefore, volume of the rubber ball = 4/3*pi*4.5^3 = 381.51 cubic inches
The answer to this is c. y=2x-6
