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Dmitry_Shevchenko [17]
3 years ago
7

Expand than simplify: -2(8p+9q)

Mathematics
1 answer:
Eva8 [605]3 years ago
5 0

Answer:

expanding ends up as the simplest form:

-16p-18q

Step-by-step explanation:

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Tính: <br> (1/27)^2016*27^2015
Alik [6]

Answer:

1/27

Step-by-step explanation:

(1/27)^2016*27^2015 =

27^-2016 * 27^2015 =

27^(-2016+2015) =

27^-1 =

1/27

6 0
3 years ago
(PLEASE ANSWER!!!! BRAINLEST!)) Quadrilateral EFGH is a scaled copy of quadrilateral ABCD. Answer the statement below as true or
Alex787 [66]
This answer would be false srry if im wrong but thats what i think
8 0
3 years ago
Pls help I have a test today in math :( no 1 would help me pls try to help and its in 12:20 so I have a lot of time but pls help
DanielleElmas [232]

Answer:

C. he did not multiply the numerator by 2

Step-by-step explanation:

To find an equivlent fraction, you must multiply the numerator and denominator by the same thing.

3 0
3 years ago
Read 2 more answers
PLEASE HELPPPPPP!!!!! You are performing an experiment to determine how well plants grow under different light sources. Of the 3
PIT_PIT [208]

The probability that a plant in the experiment receives visible or ultraviolet light is 7/10.

<u>Step-by-step explanation</u>:

The total number of plants in the experiment = 30 plants

Plants that receive visible light alone = 12 plants

Plants that receive ultraviolet light alone = 15 plants

Plants that receive both visible and ultraviolet light = 6 plants

<u>step 1</u> :

<em>Probability = No. of required events / Total number</em>

<u>step 2</u> :

P(visible) = 12 / 30

P(ultraviolet) = 15 / 30

P(both) = 6 / 30

<u>step 3</u> :

P(visible  or ultraviolet) = P(visible)  + P(ultraviolet) - P(both)

                                         = 12/30 + 15/30 - 6/30

                                         = 21/30

P(visible  or ultraviolet) = 7/10

8 0
3 years ago
Rewrite in logarithmic form 19^2 = 361
Aneli [31]

Answer:

  \log_{19}{361}=2

Step-by-step explanation:

We know that taking logarithms performs the transformation ...

  b^e=x\\\\e\cdot\log{b}=\log{x}\quad\text{take logs}\\\\e=\dfrac{\log{x}}{\log{b}}\quad\text{divide by $\log{b}$}\\\\\log_b{x}=e\quad\text{use the change of base formula}

Then for b=19, e=2, x=361, we have

  \boxed{\log_{19}{361}=2}

8 0
3 years ago
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