Answer:
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
Step-by-step explanation:
We formulate null and alternate hypotheses are
H0 : u1 < u2 against Ha: u1 ≥ u 2
Where u1 is the group tested after they were awake for 24 hours.
The Significance level alpha is chosen to be ∝ = 0.05
The critical region t ≥ t (0.05, 13) = 1.77
Degrees of freedom is calculated df = υ= n1+n2- 2= 5+10-2= 13
Here the difference between the sample means is x`1- x`2= 35-24= 11
The pooled estimate for the common variance σ² is
Sp² = 1/n1+n2 -2 [ ∑ (x1i - x1`)² + ∑ (x2j - x`2)²]
= 1/13 [ 120²+360²]
Sp = 105.25
The test statistic is
t = (x`1- x` ) /. Sp √1/n1 + 1/n2
t= 11/ 105.25 √1/5+ 1/10
t= 11/57.65
t= 0.1908
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
I: y<2*x
II: y<8
III: x>2
a: (5,3):
I: 3<2*5
3<10 ?yes
II: 3<8 ?yes
III: 5>2 ?yes
This is a solution
b: (6,0):
I: 0<2*6
0<12 ?yes
II: 0<8 ?yes
III: 6>2 ?yes
This is a solution
c: (3,3):
I: 3<2*3
3<6 ?yes
II: 3<8 ?yes
III: 3>2 ?yes
This is a solution
d: (1,-4):
I: -4<2*1
-4<2 ?yes
II: -4<8 ?yes
III: 1>2 ?no
This is not a solution
e: (4,-2):
I: -2<2*4
-2<8 ?yes
II: -2<8 ?yes
III: 4>2 ?yes
This is a solution
f: (5,9):
I: 9<2*5
9<10 ?yes
II: 9<8 ?no
This is not a solution
so a,b,c,e are solutions and d,f not
Answer:
4x+5y-34=0
Step-by-step explanation:
The slope-intercept form of a line is y=mx+b where m is the slope and b is the y-intercept.
My goal is to put in in this form first. Then I will aim to put it in general form, ax+by+c=0.
So let's give it a go:
m is the change of y over the change of x.
To compute this I'm going to line my points up and subtract vertically, then put 2nd difference over 1st difference. Like this:
( 1 , 6)
-(6 , 2)
----------
-5 4
So the slope is 4/-5 or -4/5.
So m=-4/5.
Now we are going to find b given y=mx+b and m=-4/5 and we have a point (x,y)=(1,6) [didn't matter what point you chose here].
6=-4/5 (1)+b
6=-4/5 +b
Add 4/5 on both sides:
6+4/5=b
30/5+4/5=b
34/5=b
So the y-intercept is 34/5.
The equation in slope-intercept form is:
y=-4/5 x + 34/5.
In general form, it is sometimes the goal to make all of your coefficients integers so let's do that. To get rid of the fractions, I'm going to multiply both sides by 5. This clears the 5's that were on bottom since 5/5=1.
5y=-4x+34
Now add 4x on both sides:
4x+5y=34 This is standard form.
Subtract 34 on both sides:
4x+5y-34=0
Answer:
C ) 7
Step-by-step explanation:
Constant is value in equation that DOES NOT change. Varibales such as x and y will change. Coefficent are things that are written in front of variable.
