Answer:
3x-4y=19
Step-by-step explanation:
Hi there!
We want to write the equation of the line in standard form that passes through the point (1, -4) and has the slope of 3/4
Standard form is written as ax+by=c, where a, b, and c are free integer coefficients, but a and b cannot be 0, and a cannot be negative
First, in order to find ax+by=c, we'll need to get slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
Since we already know the slope (3/4), we can substitute it into the formula for y=mx+b.
y=3/4x+b
Now we need to solve for b
Since the equation passes through the point (1, -4), we can use it to solve for b
Substitute 1 as x and -4 as y.
-4=3/4(1)+b
Multiply
-4=3/4+b
Subtract 3/4 from both sides
-19/4=b
Now substitute -19/4 as b into the equation
y=3/4x-19/4
Now we have the equation in slope-intercept form, but remember, we want it in standard form
Since x and y are on the same side in standard form, subtract 3/4x from both sides
-3/4x+y=-19/4
Remember that a cannot be negative, and the coefficients are integers (they cannot be fractions)
So in order to clear the fractions and change the sign of the equation, multiply both sides by -4
-4(-3/4x+y)=-4(-19/4)
Multiply
3x-4y=19
Hope this helps!
