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MakcuM [25]
3 years ago
12

What is -0.759 -2 = 0.25p?

Mathematics
2 answers:
a_sh-v [17]3 years ago
7 0
-2.759= 0.25p
p = -2.759/ 0.25
p = 11.036
Elis [28]3 years ago
7 0
See attached.

Isolate p.

:)

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7.4 Practice
pickupchik [31]

The simulation of the medicine and the bowler hat are illustrations of probability

  • The probability that the medicine is effective on at least two is 0.767
  • The probability that the medicine is effective on none is 0
  • The probability that the bowler hits a headpin 4 out of 5 times is 0.3281

<h3>The probability that the medicine is effective on at least two</h3>

From the question,

  • Numbers 1 to 7 represents the medicine being effective
  • 0, 8 and 9 represents the medicine not being effective

From the simulation, 23 of the 30 randomly generated numbers show that the medicine is effective on at least two

So, the probability is:

p = 23/30

p = 0.767

Hence, the probability that the medicine is effective on at least two is 0.767

<h3>The probability that the medicine is effective on none</h3>

From the simulation, 0 of the 30 randomly generated numbers show that the medicine is effective on none

So, the probability is:

p = 0/30

p = 0

Hence, the probability that the medicine is effective on none is 0

<h3>The probability a bowler hits a headpin</h3>

The probability of hitting a headpin is:

p = 90%

The probability a bowler hits a headpin 4 out of 5 times is:

P(x) = nCx * p^x * (1 - p)^(n - x)

So, we have:

P(4) = 5C4 * (90%)^4 * (1 - 90%)^1

P(4) = 0.3281

Hence, the probability that the bowler hits a headpin 4 out of 5 times is 0.3281

Read more about probabilities at:

brainly.com/question/25870256

8 0
2 years ago
Show that the equation x^4/2021 − 2021x^2 − x − 3 = 0 has at least two real roots.
andreev551 [17]

The roots of an equation are simply the x-intercepts of the equation.

See below for the proof that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} has at least two real roots

The equation is given as: \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}

There are several ways to show that an equation has real roots, one of these ways is by using graphs.

See attachment for the graph of \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}

Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)

From the attached graph, we can see that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500

This means that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} has at least two real roots

Read more about roots of an equation at:

brainly.com/question/12912962

6 0
3 years ago
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