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MakcuM [25]
3 years ago
12

What is -0.759 -2 = 0.25p?

Mathematics
2 answers:
a_sh-v [17]3 years ago
7 0
-2.759= 0.25p
p = -2.759/ 0.25
p = 11.036
Elis [28]3 years ago
7 0
See attached.

Isolate p.

:)

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Raise r to the 7th power, then double the result
Minchanka [31]

Answer:

\huge\boxed{\bf\:2r^{7}}

Step-by-step explanation:

Let the variable be taken as 'r'.

Then, by raising it to the 7th power, we'll get the result as \downarrow

 \sf\:Raise \: r \: to \: the \: 7^{th} \: power = r \: with \: 7 \: as \: its \: exponent.\\\\\sf\:Then,\\\dashrightarrow \underline{\bf\:r \: ^{7}}

Now, by doubling the result....

\sf\:To \: double \: the \: result = multiply \: the \: result \: by \: 2.\\\\\sf\:Then,\\\dashrightarrow \sf\:r \: ^{7} \\=\boxed{\bf\: 2r\:^{7}}

\rule{150pt}{2pt}

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ella [17]

Answer:

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Step-by-step explanation:

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3 years ago
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anastassius [24]
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4 years ago
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Solve<br><img src="https://tex.z-dn.net/?f=1%29%20%5C%3A%20y%20%3D%20%5Cfrac%7B37.46%7D%7B18%7D%20%5C%5C%20%5C%5C%202%29%20%5C%3
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as "Ace" you cannot operate a calculator ?

that is all that has to be done here : do the calculation !

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so, what was now the problem ?

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\bf n^{th}\textit{ term of an arithmetic sequence}&#10;\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;d=-4\\&#10;a_1=7&#10;\end{cases}&#10;\\\\\\&#10;a_n=7+(n-1)(-4)\implies a_n=7+(4-4n)&#10;\\\\\\&#10;a_n=11-4n\implies a_n=-4n+11
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