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atroni [7]
3 years ago
15

(Radioactivity) The half-life of radioactive cobalt is 5.3 years. After a nuclear reactor accident, the surrounding region had 1

00 times the amount of cobalt acceptable for habitation. How long will it be before the region is habitable?
Mathematics
1 answer:
agasfer [191]3 years ago
7 0

Answer: It will be 35 years before the region is habitable.

Step-by-step explanation:

Since we have given that

Half life of radioactive cobalt = 5.3 years

Let the initial amount of cobalt = x

final amount of cobalt = 100x

So, we need to find the time that before the region is habitable.

So, it becomes,

N=N_0(\dfrac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}\\\dfrac{N}{N_0}=(0.5)^{\frac{t}{t_{\frac{1}{2}}}}\\\dfrac{100x}{x}=0.5^{\frac{t}{5.3}}\\\\100=0.5^{\frac{t}{5.3}}\\\\\text{Taking log on both sides}\\\\\log 100=\dfrac{t}{5.3}\log 0.5\\\\\dfrac{\log 100}{\log 0.5}=\dfrac{t}{5.3}\\\\6.643\times 5.3=t\\\\35.212=t\\\\t\approx 35\ years

Hence, it will be 35 years before the region is habitable.

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Fill the missing values to make the equations true.
taurus [48]
Logarithm properties:

\displaystyle \log_a b+\log_a c=\log_a (b\cdot c)\\\\\log_ab-\log_a c=\log_a \left( \frac{b}{c} \right)\\\\\log_{a^p}b^q= \frac{q}{p} \log_a b

According to this, we can get:

\displaystyle a)\log_7 3+\log_7 8=\log_7 (3\cdot 8)=\log_724\\\\b) \log_89-\log_85=\log_8  \frac{9}{5}\\\\c)\log_325=2\log_35
3 0
3 years ago
Y = – 3
KonstantinChe [14]

The  best approximation for the solution to this system of equations is (-2.2,-3)

Option C is correct.

Step-by-step explanation:

Solving the system of equations to get the exact value of x:

y = -3\\y = x-0.8

Let

y = -3\,\,eq(1)\\y = x-0.8\,\,eq(2)

Putting value of y from eq(1) into eq(2)

-3=x-0.8

x=-3+0.8

x=-2.2

So, Value of x is -2.2

The  best approximation for the solution to this system of equations is:

x=-2.2 and y = -3

(-2.2,-3)

Option C is correct.

Keywords: System of equations

Learn more about system of equations at:

  • brainly.com/question/9045597
  • brainly.com/question/3739260
  • brainly.com/question/13168205

#learnwithBrainly

6 0
3 years ago
Read 2 more answers
Which of the following are techniques you have learned so far for solving a quadratic equation?
Usimov [2.4K]
On plato it is A AND B.

6 0
3 years ago
Question o
taurus [48]

The equation -21t - 4 = 10 - 2t has only one solution

<u>Solution:</u>

Given, equation is – 21t – 4 = 10 – 2t  

We have to find how many solutions does the above given equation have  

Now, let us solve the given equation to find the number of solutions it has.

Then, - 21t – 4 = 10 – 2t

Taking like terms to one side of the equation we get,

- 21t + 2t = 10 + 4  

\begin{array}{l}{-19 t=14} \\\\ {19 t=-14} \\\\ {t=-\frac{14}{19}}\end{array}

here we can see only one value of t.

Hence, the given equation has only one solution.

5 0
3 years ago
The length of a rectangular prism is 5 more than twice the width w. The volume of the prism is 2w^3w^2 + 5w. What's the simplifi
alekssr [168]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

<span>The length of a rectangular prism is 5 more than twice the width w. The volume of the prism is 2w^3 + w^2 + 5w. What's the simplified expression for the height of the prism
</span>
<span>V=f(w)
</span><span>2w^3 + w^2 + 5w
</span><span>v=w^2*l
</span><span>svl l=v/w^2
</span>
<span>V=w^2*(2*w+5)
</span>
<span>2w^3 + w^2 + 5w=w^2*(2*w+5)
</span><span>(2*w+5)= (2w^3 + w^2 + 5w)/w^2
w=5/4</span>
5 0
3 years ago
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