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aliina [53]
2 years ago
7

Please Help i need to know this asap

Mathematics
2 answers:
noname [10]2 years ago
6 0

Answer:

<u>(0, - 6)</u>

Step-by-step explanation:

<u>Midpoint Formula</u>

  • M = (x₁ + x₂ / 2, y₁ + y₂ / 2)

<u>Solving</u>

  • M = (-3 + 3 / 2, -7 - 5 / 2)
  • M = (0, -12/2)
  • M = <u>(0, - 6)</u>
kompoz [17]2 years ago
6 0

Answer:

The midpoint is (0, -6)

Step-by-step explanation:

<u>Step 1:  Determine the midpoint</u>

midpoint = (\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})

midpoint = (\frac{-3 + 3}{2}, \frac{-7 + (-5)}{2})

midpoint = (\frac{0}{2}, \frac{-7 -5}{2})

midpoint = (0, \frac{-12}{2})

midpoint = (0, -6)

Answer: The midpoint is (0, -6)

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Answer:

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Step-by-step explanation:

Consider the provided information.

Part (A)

The materials for each feeder cost $6, and the society sells an average of 30 per week at a price of $10 each.

Let x be the price per feeder.

Profit = Revenue - cost

So the profit per feeder is x-6

If we increase then for every dollar increase, it loses 3 sales per week.

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P(x)=-3x^2+78x-360

Hence, the required function is: P(x)=-3x^2+78x-360

Part (B) What price should the society charge for each feeder to maximize profits? What is the maximum weekly profit?

The above function is a downward parabola so the maximum will occur at vertex.

The x coordinate of the vertex of parabola is: x=\frac{-b}{2a}

Substitute a=-3, b=78 and c=-360 in above.

x=\frac{-78}{2(-3)}=13

Hence, the price for each feeder to maximize profit should be $13.

Now substitute the value of x in P(x)=-3x^2+78x-360

P(x)=-3(13)^2+78(13)-360=$147

Hence, the maximum weekly profit is $147

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3 years ago
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