Answer: The answers are given below.
Step-by-step explanation: Given that we are assembling pieces of an iron gate to complete a fence. The finished gate will look like the figure as given in the question.
Part 1: We can clearly see in the picture given that pieces 1 and 2 are placed at an angle of 90° to each other. Therefore, the pieces 1 and 2 are perpendicular to each other.
Part 2: Also, it can be seen that in the centre of the gate, the rectangular sections 5 and 6 are placed at an angle of 0° to each other. Therefore, sections 5 and 6 are parallel to each other.
Thus, 1 and 2 are perpendicular; 5 and 6 are parallel to each other.
Well, since it says it's congruent, it's congruent. EF overbar congruent to GH overbar.
A+B=15 —>A+15=B(plug this into the other equation)
60a+30b=600
60a+30(a+15)=600
60a+30a+150=600
90a+150=600
90a=450
A=5 (plug back in to first equation)
A+B=15
5+B=15
B=10
They have 5 of the Model A and 10 of model B.
