Answer:
It is an acute triangle.
Step-by-step explanation:
It would be much easier for you to see where I'm getting at if you draw a diagram.
Assume this triangle is labelled ABC where a = 14, b = 21, and c = 16.
cos A = (16^2 + 21^2 - 14^2)/(2(16)(21))
∠A = cos^-1(0.82291...)
∠A ≅ 34.6°
cos B = 16^2 + 14^2 - 21^2)/(2(16)(14))
∠B = cos^-1(0.024...)
∠B ≅ 56.8°
∠C = 180 - (∠A + ∠B)
∠C ≅ 56.8°
Since there is no right-angle nor is there an obtuse angle,
Therefore the triangle is an acute triangle.
Answer:
x-axis
Step-by-step explanation:
The horizontal number line is called the x-axis. The vertical number line is called the y-axis. The point where the x- and y-axes meet is the origin.
Hope this helps! <3
The first , second and fourth choices are correct.
Answer:
d = 6+sqrt(42)=12.4807407
Step-by-step explanation:
h= -d² + 12d + 6
The ball is caught at ground level which means h=0
0 = -d² + 12d + 6
Subtract 6 from each side
-6 = -d^2 +12d
Factor out a - sign
-6 =-(d^2-12d)
Divide by -1
6 = d^2 -12 d
Complete the square
-12/2 = -6 then square it = 36
Add 36 to each side
6+36 = d^2 -12d +36
42 = (d-6)^2
Take the square root of each side
±sqrt(42) = sqrt( (d-6)^2)
±sqrt(42) = (d-6)
Add 6 to each side
6±sqrt(42) = (d-6)+6
6±sqrt(42) = d
d = 6+sqrt(42)=12.4807407
d =6- sqrt(42)=-.480740698
Since the distance cannot be negative
