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galben [10]
3 years ago
6

What is the answer to the problem: 45.8 m x 0.385 m x 5.81 m? in sig figs?

Mathematics
1 answer:
mylen [45]3 years ago
8 0
<span>The product of these three numbers is 102.44773. The desired amount of significant figures is 3, therefore the answer to this problem is 102.</span>
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Can you help me with this thank you
Sveta_85 [38]
The correct answer is points
8 0
3 years ago
Use the Echelon Method<br> 1. Solve<br> x + 3y = 7<br> 3x + 4y = 11
Ludmilka [50]

Answer:

x = 1     y = 2

Step-by-step explanation:

x + 3y = 7

- Subtract x from both sides.

3y = -x + 7

- Divide both sides by 3 to isolate the variable.

y = -1/3x + 7/3

- Plug the value of y into the other equation.

3x + 4(-1/3x + 7/3) = 11

3x - 4/3x + 28/3 = 11

- Add like terms.

5/3x + 28/3 = 11

5/3x = 5/3

x = 1

- Plug the value of x into the equation.

x + 3y = 7

(1) + 3y = 7

3y = 6

y = 2

5 0
3 years ago
Solve for the exact values of x and y.<br> x = <br> y =
Soloha48 [4]

Answer:

Here is the solution...hope it helps:)

7 0
2 years ago
Wich graph matches the equition x=5
svetlana [45]
Option 1
because the x line is vertical and that’s the only one that crosses at 5
8 0
2 years ago
Read 2 more answers
Find the limiting value using L hospital​
viktelen [127]

Answer:

  -1

Step-by-step explanation:

The expression evaluates to the indeterminate form -∞/∞, so L'Hopital's rule is appropriately applied. We assume this is the common log.

  d(log(x))/dx = 1/(x·ln(10))

  d(log(cot(x)))/dx = 1/(cot(x)·ln(10)·(-csc²(x)) = -1/(sin(x)·cos(x)·ln(10))

Then the ratio of these derivatives is ...

  lim = -sin(x)cos(x)·ln(10)/(x·ln(10)) = -sin(x)cos(x)/x

__

At x=0, this has the indeterminate form 0/0, so L'Hopital's rule can be applied again.

  d(-sin(x)cos(x))/dx = -cos(2x)

  dx/dx = 1

so the limit is ...

  lim = -cos(2x)/1

  lim = -1 when evaluated at x=0.

_____

I find it useful to use a graphing calculator to give an estimate of the limit of an indeterminate form.

5 0
2 years ago
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