The correct answer is points
Answer:
x = 1 y = 2
Step-by-step explanation:
x + 3y = 7
- Subtract x from both sides.
3y = -x + 7
- Divide both sides by 3 to isolate the variable.
y = -1/3x + 7/3
- Plug the value of y into the other equation.
3x + 4(-1/3x + 7/3) = 11
3x - 4/3x + 28/3 = 11
- Add like terms.
5/3x + 28/3 = 11
5/3x = 5/3
x = 1
- Plug the value of x into the equation.
x + 3y = 7
(1) + 3y = 7
3y = 6
y = 2
Answer:
Here is the solution...hope it helps:)
Option 1
because the x line is vertical and that’s the only one that crosses at 5
Answer:
-1
Step-by-step explanation:
The expression evaluates to the indeterminate form -∞/∞, so L'Hopital's rule is appropriately applied. We assume this is the common log.
d(log(x))/dx = 1/(x·ln(10))
d(log(cot(x)))/dx = 1/(cot(x)·ln(10)·(-csc²(x)) = -1/(sin(x)·cos(x)·ln(10))
Then the ratio of these derivatives is ...
lim = -sin(x)cos(x)·ln(10)/(x·ln(10)) = -sin(x)cos(x)/x
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At x=0, this has the indeterminate form 0/0, so L'Hopital's rule can be applied again.
d(-sin(x)cos(x))/dx = -cos(2x)
dx/dx = 1
so the limit is ...
lim = -cos(2x)/1
lim = -1 when evaluated at x=0.
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I find it useful to use a graphing calculator to give an estimate of the limit of an indeterminate form.