Let "x" be the positive integer
Twenty times a square of a positive integer plus 50:
20x² + 50
Negative 40 times the square of the positive integer plus one-hundred and ten times the positive integer:
-40x² + 100x
The equation could be used is shown below:
20x² + 50 = -40x² +100x
20x² + 40x² -100x + 50 = 0
60x² - 100x +50 =0
Move variable to right -
-3Y=9-5x
Divide both sides by -3 -
y=-3+5 over 3 x 5/3 x(not right besides the 3 it is on the end)
Answer:x/5 + 2b/5
Step-by-step explanation:
9a-2b=c+4a solve for a
9a-2b=c+4a
add -4a to both sides
9a-4a-2b=x+4a-4a
5a-2b=x
add 2b to both sides
5a-2b+2b=x+2b
5a= x+2b
divide by 5
5a/5 = x/5 +2b/5
a= x/5 + 2b/5
Answer: what would the answer be?
Step-by-step explanation:
I think the answer is C.
First start by factoring, you should get (2n-3)(n-2)=0
Then start to solve for n.
2n-3=0
n-2=0
n=2, n= 3/2
I hope that helps.
