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Burka [1]
3 years ago
7

When h has the value 4 calculate 4h+9

Mathematics
1 answer:
nika2105 [10]3 years ago
5 0
25 is your answer. 4X4+9= 25
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Can someone check if this is right or did I solve it wrong?
ICE Princess25 [194]

Answer:

f(3x) - 2g(x+1) = 12x - 5

Step-by-step explanation:

You've got f[g(x)] and g[f(x)] correct

However, f(3x) means substitute 3x for x in f(x):

f(3x) = 2(3x) - 3

⇒ f(3x) = 6x - 3

2g(x+1) = 2[4 - 3(x + 1)]

⇒ 2g(x+1) = 2[4 - 3x -3]

⇒ 2g(x+1) = 2[1 - 3x]

⇒ 2g(x+1) = 2 - 6x

f(3x) - 2g(x+1) = (6x - 3) - (2 - 6x)

⇒ f(3x) - 2g(x+1) = 12x - 5

4 0
2 years ago
Find the mass of the solid paraboloid Dequals=​{(r,thetaθ​,z): 0less than or equals≤zless than or equals≤8181minus−r2​, 0less th
Lubov Fominskaja [6]

Answer:

M = 5742π  

Step-by-step explanation:

Given:-

- Find the mass of a solid with the density ( ρ ):

                             ρ ( r, θ , z ) = 1 + z / 81

- The solid is bounded by the planes:

                             0 ≤ z ≤ 81 - r^2

                             0 ≤ r ≤ 9

Find:-

Find the mass of the solid paraboloid

Solution:-

- The mass (M) of any solid body is given by the following triple integral formulation:

                           M = \int \int \int {p ( r ,theta, z)} \, dV\\\\

- We can write the above expression in cylindrical coordinates:

                           M = \int\limits\int\limits_r\int\limits_z {r*p(r,theta,z)} \, dz.dr.dtheta \\\\M = \int\limits\int\limits_r\int\limits_z {r*[ 1 + \frac{z}{81}] } \, dz.dr.dtheta\\\\

- Perform integration:

                           M = \int\limits\int\limits_r{r*[ z + \frac{z^2}{162}] } \,|_0^8^1^-^r^2 dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{(81-r^2)^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + \frac{6561 -162r + r^2}{162}] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{r*[ 81-r^2 + 40.5 -r +\frac{r^2}{162} ] } \, dr.dtheta\\\\M = \int\limits\int\limits_r{[ 121.5r-r^2 -\frac{161r^3}{162} ] } \, dr.dtheta\\\\

                           M = 2*\int\limits_0^\pi {[ 121.5r^2-r^3 -\frac{161r^4}{162} ] } |_0^6 \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 121.5(6)^2-(6)^3 -\frac{161(6)^4}{162} ] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 4375-216 -1288] }  \, dtheta\\\\M = 2*\int\limits_0^\pi {[ 2871] }  \, dtheta\\\\M = 5742\pi  kg              

- The mass evaluated is M = 5742π                      

8 0
2 years ago
Addison worked 11 more hours this week than last week. In total, she worked 65 hours this week and last week. Using the equation
Anestetic [448]

Answer:

27 hours

Step-by-step explanation:

Just do the reverse. 65-11 = 54. 54 / 2 = 27.

5 0
2 years ago
I need help ASAP on this algebra question
Misha Larkins [42]

Answer:

As x goes to negative infinity, g(x) goes to zero.

As x goes to positive infinity, g(x) goes to zero.

(So the answer is the second option)

Step-by-step explanation:

We have the function g(x)=\frac{1}{x^2}

First, let's look at what happens when we input smaller and smaller numbers

g(-10)=\frac{1}{100} \\\\g(-100)=\frac{1}{10000}

As we can see, as we input smaller and smaller numbers, the answer gets smaller.

Eventually, these fractions will be so small that they will get closer and closer to zero.

This same thing applies to larger and larger numbers, so the end behavior of each side will both be zero.

4 0
2 years ago
How many terms are in 5x4-2x3+x-4
san4es73 [151]
I think that there are 4 termms if we condider onlu plus and minus as operators.
7 0
2 years ago
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