The graph shown meets the conditions -3 ≤ y ≤ 3. True or False

IF YOU ANSWER THIS I WILL GIVE YOU BRAINLIEST!! 21PTS

vovangra [49]

200 < 225 + 80x < 550

The 200 is the amount the Jenna currently have.
225 + 80x is the amount that Jenna has to pay given x number of hours.
550 is the sum of Jenna's 200 and additional 350 she can get by selling pre-ordered Cds. This is the maximum amount she can pay for the studio rental and sound technicians.

225 + 80x < 550
80x < 550 -225
80x < 325
80x / 80 < 325/80
x < 4.06 or 4 hours

225 + 80x → 225 + 80(4) = 225 + 320 = 545

The number of hours for the sound technician will range from 1 hour to 4 hours.

Assuming they will use 6 hours.

225 + 80(6) = 225 + 480 = 705
705 - 550 = 155

Jenna has to raise an additional $155 to pay off the studio rent and 6 hours of sound technicians.

4 0

2 years ago

Find a consecutive odd numbers where the sum of the first three numbers is 15 greater then the final two numbers.

xenn [34]

Answer:

15, 17, 19

Step-by-step explanation:

x + x+2 + x+4 = 15 + (x+2 + x+4)

3x + 6 = 15 + 2x + 21

x = 15

x+2 = 17

x+4 = 19

4 0

2 years ago

true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp

Goshia [24]

Answer:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

6 0

2 years ago

Can u help me with this full sheet of work

nadezda [96]

Sometimes it takes a while to learn them but youll get it:)
1. she
2. they
3. him
4. she
5. them
6. it
7. Nate, he
8. Juwon, him
9. the sky, it
10. Mrs. P, her
11. a great catch, it
12. the coach, his OR new players, they

6 0

2 years ago

Read 2 more answers

A random sample of 20 houses selected from a city showed that the mean size of these houses is 1880 square feet with a standard

azamat

Answer:

Option C

Step-by-step explanation:

Given that for a random sample of 20 houses selected from a city showed that the mean size of these houses is 1880 square feet with a standard deviation of 320 square feet.

X, the sizes of houses is Normal

Hence sample mean will be normal with

Mean = 1880

and std dev = $\frac{320}{\sqrt{20} } \\=71.5542$

For 90% confidence interval critical value for t with degree of freedom 19 is

1.328

Confidence interval upper bound

= mean + margin of error

= $1880+1.328*71.55\\=1975$

Option C is right

3 0

3 years ago