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asambeis [7]
3 years ago
5

Help me please. i attached an image.

Mathematics
2 answers:
timofeeve [1]3 years ago
8 0
The measure of BEC is 30
kap26 [50]3 years ago
4 0
You answer is 45. I’m ok at math so don’t take it personally if I get it wrong!
You might be interested in
If $6000 was expected in sales and only $5100 was attained, what reduced fraction represents sales attained?
ira [324]

The reduced fraction that represents the sales attained is 17/20

<h3>How to determine the fraction?</h3>

The given parameters are:

Expected = $6000

Attained = $5100

The fraction is represented as:

Fraction = Attained/Expected

So, we have:

Fraction = 5100/6000

Divide by 300

Fraction = 17/20

Hence, the reduced fraction is 17/20

Read more about fractions at:

brainly.com/question/1622425

#SPJ1

7 0
2 years ago
Which expression is equivalent to 21 × 7?
belka [17]

I wanna say the answer is A

6 0
3 years ago
A collection of stamps consists of 22¢ stamps and 40¢ stamps. The number of 22¢ stamps is three more than four times the number
Artemon [7]

Answer:

27

Step-by-step explanation:

Let :

Number of 40¢ = x

Number of 22¢ = 4x + 3

Total stamp value = $8.34 = (8.34 * 100) = 834¢

40¢x + 22¢(4x + 3) = 834¢

40x + 88x + 66 = 834

128x = 834 - 66

128x = 768

x = 768 / 128

x = 6

Number of 22¢ stamp:

4(6) + 3 = 24 + 3 = 27

7 0
3 years ago
A group of 29 friends get together to play a sport first person must be divided into team each team has to have exactly 4 player
telo118 [61]

Answer:

7 teams remaining a person

Step-by-step explanation:

29/4 = 7 remainder 1

5 0
2 years ago
Find f(g(x)). State the domain of the composite function.<br> f(x) = 3x-2/x+1<br> g(x) = x+5/2x-3
AnnyKZ [126]

Answer:

ℝ - {(-2/3),(3/2)}

Step-by-step explanation:

We want the domain of f(g(x)). So, firstly, we have to find the domain for g(x) and, then, for f(g(x)).

- Domain of g(x): Since the expression is a fracion, we must exclude the values of x that make null the denominator. Hence,

g(x)=\dfrac{x+5}{2x-3}\Longrightarrow 2x-3\neq 0\iff \boxed{x\neq\dfrac{3}{2}}

- Domain of f(g(x)): We'll find its expression:

f(x) = \dfrac{3x-2}{x+1}\\\\f(g(x)) = \dfrac{3g(x)-2}{g(x)+1}\\\\f(g(x)) = \dfrac{3\cdot\dfrac{x+5}{2x-3}-2}{\dfrac{x+5}{2x-3}+1}=\dfrac{~~~\dfrac{3(x+5)-2(2x-3)}{2x-3}~~~}{\dfrac{(x+5)+(2x-3)}{2x-3}}\\\\f(g(x)) =\dfrac{3(x+5)-2(2x-3)}{(x+5)+(2x-3)}=\dfrac{3x+15-4x+6}{x+5+2x-3}\\\\\boxed{f(g(x)) =\dfrac{21-x}{3x+2}}

Now, once again, we have to exclude the values of x that make the denominator equals to zero. Thus,

f(g(x)) =\dfrac{21-x}{3x+2}\Longrightarrow 3x+2\neq0\iff \boxed{x\neq-\dfrac{2}{3}}

Lastly, we may write the domanin of f(g(x)):

D(f(g(x)) = \left]-\infty,-\dfrac{2}{3}\right[\cup\left]-\dfrac{2}{3},\dfrac{3}{2}\right[\cup\left]\dfrac{3}{2},\infty\right[

or, just writing in a shorter way:

\boxed{D(f(g(x)) = \mathbb{R}-\left\{-\dfrac{2}{3},\dfrac{3}{2}\right\}}

7 0
2 years ago
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