All categories

3 years ago

Is -¼ + 2 ¼y + 2 - y equivalent to y + 2 ?

Mathematics

1 answer:

Juliette [100K]3 years ago

5 0

Answer: No

Step-by-step explanation:

$-\frac{1}{4}+2\frac{1}{4}y+2-y=y+2$

$(-\frac{1}{4}+2)+(2\frac{1}{4}y-y)=y+2\\$

$(\frac{(-1)+(4)(2)}{4})+(\frac{9}{4}y-y)=y+2$

$(\frac{-1+8}{4})+(\frac{(9)(1)-(4)(1)}{4} )y=y+2$

$(\frac{7}{4})+(\frac{9-4}{4} )y=y+2$

$(\frac{7}{4})+(\frac{5}{4})y=y+2$

You might be interested in

Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15

Digiron [165]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\left. \begin{array} { l } { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.$

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$2x-5y=-13, \: 3x+4y=15$

Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

$2x-5y=-13$

Add 5y to both sides of the equation.

$2x=5y-13$

Divide both sides by 2.

$x=\frac{1}{2}\left(5y-13\right) \\$

Multiply $\frac{1}{2}\\$ times 5y - 13.

$x=\frac{5}{2}y-\frac{13}{2} \\$

Substitute $\frac{5y-13}{2}\\$ for x in the other equation, 3x + 4y = 15.

$3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15 \\$

Multiply 3 times $\frac{5y-13}{2}\\$ .

$\frac{15}{2}y-\frac{39}{2}+4y=15 \\$

Add $\frac{15y}{2} \\$ to 4y.

$\frac{23}{2}y-\frac{39}{2}=15 \\$

Add $\frac{39}{2}\\$ to both sides of the equation.

$\frac{23}{2}y=\frac{69}{2} \\$

Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

$\large \underline{ \underline{ \sf \: y=3 }}$

Substitute 3 for y in $x=\frac{5}{2}y-\frac{13}{2}\\$ . Because the resulting equation contains only one variable, you can solve for x directly.

$x=\frac{5}{2}\times 3-\frac{13}{2} \\$

Multiply 5/2 times 3.

$x=\frac{15-13}{2} \\$

Add $-\frac{13}{2}\\$ to $\frac{15}{2}\\$ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

$\large\underline{ \underline{ \sf \: x=1 }}$

The system is now solved. The value of x & y will be 1 & 3 respectively.

$\huge\boxed{ \boxed{\bf \: x=1, \: y=3 }}$

8 0

2 years ago

If George is 33 1/3% richer than Pete, than Pete is what percent poorer than George?

OleMash [197]

Answer:

25%

Step-by-step explanation:

George is 33 $\frac{1}{3}$ % ( $\frac{100}{3}$ %) richer than Pete. Let Pete's percentage of wealth be 100%.

Thus George percentage of wealth = 100% + $\frac{100}{3}$ %

= $\frac{400}{3}$ %

= 133 $\frac{1}{3}$ %

Pete's percent poorer than George can be determined by;

= $(\frac{100}{3})$ ÷ $(\frac{400}{3} )$ × 100

= $(\frac{100}{3})$ × $\frac{3}{400}$ ×100

= 0.25 × 100

= 25%

Pete is 25% poorer than George.

3 0

3 years ago

What types of solutions does 6x^2 - 20x + 1 have?

elena55 [62]

Answer:

2 real solutions

Step-by-step explanation:

We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:

b² - 4ac

If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.

Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:

b² - 4ac

(-20)² - 4 * 6 * 1 = 400 - 24 = 376

Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.

<em>~ an aesthetics lover</em>

3 0

2 years ago

What is the value of y

guajiro [1.7K]

Answer:

Step-by-step explanation:

From Thales' theorem:

$\dfrac y7\ =\ \dfrac45\\\\y=\dfrac45\cdot7\\\\y = \dfrac{28}5\\\\y = 5.6$

5 0

3 years ago

F(x)=x^2(x+3)^2 <br><br> How do I find the roots of this equation?

Genrish500 [490]

= x^2 ( x+3 ) (x+3)
= set equal to 0

X^2= 0
X=0

X+3=0
X=-3

Answer is -3 and 0

6 0

2 years ago