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Ugo [173]
4 years ago
7

80% of your employees work in production.What fraction of the employees work in production?

Mathematics
2 answers:
jek_recluse [69]4 years ago
7 0
Well turn a percentage into a fraction is simple. Just put the first number of the percentage over a fraction of 10, or if the percentage also has a second number that's not 0, put both numbers over a fraction of 100.

So the correct answer would be 8/10

Hope this helped. Have a great day!
Alex Ar [27]4 years ago
4 0
0.8 of employees work in production
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3 years ago
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given the weekly demand curve of a local wine producer is p= 50-0.1q, and that the total cost function is c= 1500+ 10q, where q
ipn [44]

Answer:

a)the weekly profit as a function of price isP=-10 p^2 + 600 p - 6500

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

Step-by-step explanation:

The weekly demand curve of a local wine producer is p= 50-0.1q

p = price

q = quantity

Revenue function R =Price \times Quantity

R=(50-0.1q)q

R=50q-0.1q^2

Cost function: c= 1500+ 10q

Profit function=R(x)-C(x)

Profit function= 50q-0.1q^2-1500-10q

Profit function= 40q-0.1q^2-1500   ----1

We have q = 500 - 10 p using p = 50 − 0.1q

P=-0.1 (500 - 10 p)^2 + 40 (500 - 10 p)- 1500\\P= -10 p^2 + 600 p - 6500

General quadratic equation:ax^2+bx+c=0

On comparing

a = -0.1 , b = 40 , c = -1500

Maximum Profit is at q = \frac{-b}{2a}=\frac{-40}{2(-0.1)}=200

To find price must a bottle of wine be sold to realise maximum profit

p= 50-0.1q

p= 50-0.1(200)=30

Substitute the value of q in profit function(1) get the maximum profit

So, Profit function= 40\left(200\right)-0.1\left(200\right)^{2}-1500=2500

Hence

a)the weekly profit as a function of price isP=-10 p^2 + 600 p - 6500

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

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= 10x - 9x - 2y + 3y

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