Ask question

Ask question

All categories

2 years ago

14

DONTTTTTTTT SKIPPPPPPPPPPP answer both

2 answers:

elena-14-01-66 [18.8K]2 years ago

6 0

For the first question I believe it’s 3,2 and 2,3

Citrus2011 [14]2 years ago

5 0

Yo my mans that mad easy

You might be interested in

Find the circumference and the area of a circle with radius 8 yd.

Bezzdna [24]

Answer:

Area: 200.96yd²

Circumference: 50.24yd

Step-by-step explanation:

See attached image

8 0

2 years ago

Read 2 more answers

If anyone can help me I’ll give all my points to u..

balu736 [363]

Answer: 12x squared

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

The equation of the line in this graph is<br>y= ____ x+____ .<br>

Alexxx [7]

The equation of the line in this graph is y = 3/2x + 3.

Explanation:

In slope intercept form equations, the initial value is where everything begins. In this equation, that would be at the point (0,3). From there, because it is going up toward the right side, there is a positive slope. The formula for slope is rise over run, so to get our slope, we have to go up 3 units and over 2 units.

3 0

2 years ago

The sides of a rectangle have a length of x + 4 units and a width of 2x + 5 units. Which

kirill115 [55]

Step-by-step explanation:

4-1-2-3-4-6-910191944

8 0

3 years ago

given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these

lesya [120]

Answer:

Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

$a_{n}=a_{n-1}*r$

so comparing it with the given recursive formula $a_{n}=a_{n-1}*-4$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.$

Explicit Formula = $-2*(-4)^{n-1}$

2) Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.$

Explicit Formula = $-4*(-2)^{n-1}$

3)Comparing the given recursive formula $a_{n}=a_{n-1}*3$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =3

8th term= $a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.$

Explicit Formula = $-1*(3)^{n-1}$

4)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.$

Explicit Formula = $3*(-4)^{n-1}$

5)Comparing the given recursive formula $a_{n}=a_{n-1}*-4$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-4

8th term= $a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.$

Explicit Formula = $-4*(-4)^{n-1}$

6)Comparing the given recursive formula $a_{n}=a_{n-1}*-2$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-2

8th term= $a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.$

Explicit Formula = $3*(-2)^{n-1}$

7)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.$

Explicit Formula = $4*(-5)^{n-1}$

8)Comparing the given recursive formula $a_{n}=a_{n-1}*-5$

with standard recursive formula $a_{n}=a_{n-1}*r$

we get common ratio =-5

8th term= $a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.$

Explicit Formula = $2*(-5)^{n-1}$

6 0

3 years ago