All categories

3 years ago

What is the advantage of saving a document as a PDF file?

Computers and Technology

1 answer:

Sindrei [870]3 years ago

3 0

Answer:It can be opened by most computers.

Explanation: it is a widely used file type that is able to be opend in a web browser if no PDF viewer app is instlled like Adobe.

You might be interested in

Which command is used to combine two or more cells together into one cell?

Tju [1.3M]

B is your answer I believe

5 0

3 years ago

Read 2 more answers

Whose email address may the agent enter into the applicant information section of LEAN enrollment application

stich3 [128]

It is the customer's email address may be entered into the applicant information section of LEAN enrollment application

<h3>What is LEAN enrollment application?</h3>

LEAN enrollment application is a kind of electronic enrollment program which is specifically designed to make enrollments easier for agent

So therefore, It is the customer's email address which may be entered into the applicant information section of LEAN enrollment application

Learn more about enrollment application:

brainly.com/question/18186504

#SPJ1

6 0

2 years ago

Write a program to prompt the user for hours and rate per hour using input to compute gross pay. Pay the hourly rate for the hou

Nuetrik [128]

Answer:

Following is the program in the python language

hr = input("input hours:") #Read input by user

h1 = float(hr)

rate =input("Input Rate:") #Read RATE BY USER

r1 = float(rate) #CONVERT INTO FLOAT

if h1 <= 40: #check condition

t=h1 * r1

print (t) #DISPLAY

else :#else block

t1=(40 * r1) + (h1 -40) * r1 * 1.5

print('The pay is :')

print(t1)#DISPLAY

Output:

input hours:45

Input Rate:10.50

The pay is :

498.75

Explanation:

Following are the description of program

Read the value of hour in the "hr" variable and convert into the float value in the "h1" variable .
Read the value of rate in the " rate" variable and convert into the float value in the "r1" variable .
After that check the condition of hour if block if the hour is less then or equal to 40 then it multiplied h1 *t1 otherwise else block will be executed and print the value of pay .

5 0

4 years ago

Using Matlab programming I need to rotate the line defined by x,y by 45 degrees around 2,2

belka [17]

Answer:

% here x and y is given which we can take as

x = 2:2:10;

y = 2:2:10;

% creating a matrix of the points

point_matrix = [x;y];

% center point of rotation which is 2,2 here

x_center_pt = x(2);

y_center_pt = y(2);

% creating a matrix of the center point

center_matrix = repmat([x_center_pt; y_center_pt], 1, length(x));

% rotation matrix with rotation degree which is 45 degree

rot_degree = pi/4;

Rotate_matrix = [cos(rot_degree) -sin(rot_degree); sin(rot_degree) cos(rot_degree)];

% shifting points for the center of rotation to be at the origin

new_matrix = point_matrix - center_matrix;

% appling rotation

new_matrix1 = Rotate_matrix*new_matrix;

Explanation:

We start the program by taking vector of the point given to us and create a matrix by adding a scaler to each units with repmat at te center point which is (2,2). Then we find the rotation matrix by taking the roatational degree which is 45 given to us. After that we shift the points to the origin and then apply rotation ans store it in a new matrix called new_matrix1.

4 0

4 years ago

Create a function void process(char ch, int x, int y)- to accept an arithmetic operator (+,-./, in argum

saul85 [17]

Answer:

The program is as follows:

import java.util.*;

public class Main{

public static void process(char ch, int x, int y){

if(ch == '+'){

System.out.print(x+y); }

else if(ch == '-'){

System.out.print(x-y); }

else if(ch == '*'){

System.out.print(x*y); }

else if(ch == '/'){

if(y!=0){

double num = x;

System.out.print(num/y); }

else{

System.out.print("Cannot divide by 0"); } }

else{

System.out.print("Invalid operator"); }

}

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

int x, y;

char ch;

System.out.print("Enter two integers: ");

x = input.nextInt(); y = input.nextInt();

System.out.print("Enter operator: ");

ch = input.next().charAt(0);

process(ch,x, y);

}

Explanation:

The function begins here

public static void process(char ch, int x, int y){

If the character is +, this prints the sum of both integers

if(ch == '+'){

System.out.print(x+y); }

If the character is -, this prints the difference of both integers

else if(ch == '-'){

System.out.print(x-y); }

If the character is *, this prints the product of both integers

else if(ch == '*'){

System.out.print(x*y); }

If the character is /, this prints the division of both integers.

else if(ch == '/'){

if(y!=0){

double num = x;

System.out.print(num/y); }

else{

This is executed if the denominator is 0

System.out.print("Cannot divide by 0"); } }

Invalid operator is printed for every other character

else{

System.out.print("Invalid operator"); }

}

The main begins here

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

This declares both integers

int x, y;

This declares the operator

char ch;

Get input for both integers

System.out.print("Enter two integers: ");

x = input.nextInt(); y = input.nextInt();

Get input for the operator

System.out.print("Enter operator: ");

ch = input.next().charAt(0);

Call the function

process(ch,x, y);

}

6 0

3 years ago