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coldgirl [10]
3 years ago
5

What is the answer?​

Mathematics
1 answer:
andreev551 [17]3 years ago
7 0

\bf \begin{array}{cll} \cfrac{1}{3}\\\\\cline{1-1}\\ \cfrac{1}{9}~~\cfrac{1}{9}~~\cfrac{1}{9} \end{array}\qquad \implies\qquad \cfrac{1}{3}=\cfrac{1+1+1}{9}\implies \cfrac{1}{3}= \cfrac{3}{9} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{array}{cll} \cfrac{1}{4}\\\\\cline{1-1}\\ \cfrac{1}{8}~~\cfrac{1}{8} \end{array}\qquad \implies\qquad \cfrac{1}{4}=\cfrac{1+1}{8}\implies \cfrac{1}{4}= \cfrac{2}{8}

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Answer:

<u>Equation</u>:  F=1500(1.0025)^{12t}

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<u></u>

Step-by-step explanation:

This is a compound growth problem . THe formula is:

F=P(1+\frac{r}{n})^{nt}

Where

F is future amount

P is present amount

r is rate of interest, annually

n is the number of compounding per year

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Given:

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The compound interest formula modelled by the variables is:

F=1500(1+\frac{0.03}{12})^{12t}\\F=1500(1.0025)^{12t}

Now, we want balance after 5 years, so t = 5, substituting, we get:

F=1500(1.0025)^{12t}\\F=1500(1.0025)^{12*5}\\F=1500(1.0025)^{60}\\F=1742.43

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