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coldgirl [10]
4 years ago
5

What is the answer?​

Mathematics
1 answer:
andreev551 [17]4 years ago
7 0

\bf \begin{array}{cll} \cfrac{1}{3}\\\\\cline{1-1}\\ \cfrac{1}{9}~~\cfrac{1}{9}~~\cfrac{1}{9} \end{array}\qquad \implies\qquad \cfrac{1}{3}=\cfrac{1+1+1}{9}\implies \cfrac{1}{3}= \cfrac{3}{9} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{array}{cll} \cfrac{1}{4}\\\\\cline{1-1}\\ \cfrac{1}{8}~~\cfrac{1}{8} \end{array}\qquad \implies\qquad \cfrac{1}{4}=\cfrac{1+1}{8}\implies \cfrac{1}{4}= \cfrac{2}{8}

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Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
A sports teacher had 1025 sweets. After distributing these equally amongst all the participants in a sports meet, he had just 1
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Step-by-step explanation:

Since it remains only 1 sweet, we can subtract it from the total and get the amount of sweets distributed (=1024).

As all the sweets are distributed equally, we must divide the number of distributed sweets by all its dividers (excluding 1024 and 1, we'll see later why):

1) 512 => 2 partecipants

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The number on the left represents the number of sweets given to the partecipants, and on the right we have the number of the partecipants. Note that all the numbers on the left are dividers of 1024.

Why excluding 1 and 1024? Because the problem tells us that there remains 1 sweet. If there was 1 sweet for every partecipant, the number of partecipants would be 1025, but that's not possible as there remains 1 sweet. If it was 1024, it wouldn't work as well because the sweets are 1025 and if 1 is not distributed it goes again against the problem that says all sweets are equally distributed.

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3 years ago
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what do you mean ¨ what is the distance between¨ what is the rest of the question?


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3 years ago
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