Answer:
(a) The change in energy of the atom is --6.0528 X 10⁻²⁰ J
(b) The wavelength of the photon is 32841 Å
Explanation:
E = -kz²/n²
Where;
E is the change in the energy of the atom
k is a constant = 2.179 X 10¹⁸ J
z is the atomic number of hydrogen = 1
n = 6
E = -(1 X 2.179 X 10⁻¹⁸ )/6²
E = -6.0528 X 10⁻²⁰ J
Therefore,the change in energy of the atom is -6.0528 X 10⁻²⁰ J
(b) the wavelength (in Å) of the photon, can be calculated as follows;
E = hc/λ
λ = hc/E
where;
h is Planck's constant = 6.626 X 10⁻³⁴ js
c is the speed of light = 3 X 10⁸ m/s
λ is the wavelength of the photon
λ = (6.626 X 10⁻³⁴ X 3 X 10⁸ )/(6.0528 X 10⁻²⁰)
λ = 3.2841 X 10⁻⁶ m
λ = 32841 Å
Therefore, the wavelength of the photon is 32841 Å
