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3 years ago

As the organsims develops, its cells become -------

Chemistry

1 answer:

exis [7]3 years ago

3 0

It's cells become larger in numbers.

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When humans burn fossil fuels, most of the the carbon quickly enters the atmosphere as carbon dioxide in the atmosphere in the p

nevsk [136]

Transpiration i think

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3 years ago

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If the container is closed and the ethanol is allowed to reach equilibrium with its vapor, how many grams of liquid ethanol rema

SVETLANKA909090 [29]

Explanation:

Let us assume that the given data is as follows.

V = 3.10 L, T = $19^{o}C$ = (19 + 273)K = 292 K

P = 40 torr (1 atm = 760 torr)

So, P = $\frac{40 torr}{760 torr} \times 1 atm$

= 0.053 atm

n = ?

According to the ideal gas equation, PV = nRT.

Putting the given values into the above equation to calculate the value of n as follows.

PV = nRT

$0.053 atm \times 3.10 L = n \times 0.0821 L atm/mol K \times 292 K$

0.1643 = $n \times 23.97$

n = $6.85 \times 10^{-3}$

It is known that molar mass of ethanol is 46 g/mol. Hence, calculate its mass as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

$6.85 \times 10^{-3} = \frac{mass}{46 g/mol}$

mass = $315.1 \times 10^{-3}$ g

= 0.315 g

Thus, we can conclude that the mass of liquid ethanol is 0.315 g.

4 0

3 years ago

PLEASE HELP When I combine Sprite with a sour candy, it starts to bubble a lot. Is this a physical or chemical change?

maksim [4K]

Answer:

B. chemical

Explanation:

Chemical change cannot go back to its original form

4 0

2 years ago

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12. The vapor pressure of water at 90°C is 0.692 atm. What is the vapor pressure (in atm) of a solution made by dissolving 3.68

luda_lava [24]

Answer : The vapor pressure (in atm) of a solution is, 0.679 atm

Explanation : Given,

Mass of $H_2O$ = 1.00 kg = 1000 g

Moles of $CsF$ = 3.68 mole

Molar mass of $H_2O$ = 18 g/mole

Vapor pressure of water = 0.692 atm

First we have to calculate the moles of $H_2O$ .

$\text{Moles of }H_2O=\frac{\text{Mass of }H_2O}{\text{Molar mass of }H_2O}=\frac{1000g}{18g/mole}=55.55mole$

Now we have to calculate the mole fraction of $H_2O$

$\text{Mole fraction of }H_2O=\frac{\text{Moles of }H_2O}{\text{Moles of }H_2O+\text{Moles of }CsF}=\frac{55.55}{55.55+3.68}=0.938$

Now we have to partial pressure of solution.

According to the Raoult's law,

$P_{Solution}=X_{H_2O}\times P^o_{H_2O}$

where,

$P_{Solution}$ = vapor pressure of solution

$P^o_{H_2O}$ = vapor pressure of water = 0.692 atm

$X_{H_2O}$ = mole fraction of water = 0.938

$P_{Solution}=X_{H_2O}\times P^o_{H_2O}$

$P_{Solution}=0.938\times 0.692atm$

$P_{Solution}=0.649atm$

Therefore, the vapor pressure (in atm) of a solution is, 0.679 atm

5 0

2 years ago

PLEASE HELP

HACTEHA [7]

Not sure gets hotter prolly

5 0

2 years ago

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