Answer:
Mole Fraction (H₂O) = 0.6303
Mole Fraction (C₂H₅OH) = 0.3697
Explanation:
(Step 1)
Calculate the mole value of each substance using their molar masses.
Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol
Molar Mass (H₂O): 18.014 g/mol
200.0 g H₂O 1 mole
--------------------- x ------------------ = 11.10 moles H₂O
18.014 g
Molar Mass (C₂H₅OH): 2(12.011 g/mol) + 6(1.008 g/mol) + 15.998 g/mol
Molar Mass (C₂H₅OH): 46.068 g/mol
300.0 g C₂H₅OH 1 mole
---------------------------- x -------------------- = 6.512 moles C₂H₅OH
46.068 g
(Step 2)
Using the mole fraction ratio, calculate the mole fraction of each substance.
moles solute
Mole Fraction = ------------------------------------------------
moles solute + moles solvent
11.10 moles H₂O
Mole Fraction = -------------------------------------------------------------
11.10 moles H₂O + 6.512 moles C₂H₅OH
Mole Fraction (H₂O) = 0.6303
6.512 moles C₂H₅OH
Mole Fraction = -------------------------------------------------------------
11.10 moles H₂O + 6.512 moles C₂H₅OH
Mole Fraction (C₂H₅OH) = 0.3697
Answer:
* Beryllium is the lightest of all the alkaline earth metals.
* It has higher melting and boiling points compared to other elements in group 2.
Explanation:
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In an equation, 40kJ + 2SO₃ (g) -->2SO₂(g) + O₂(g), if pressure added, the equilibrium shifts to the left side of the reaction because it has fewer moles of gas.
<h3>What is Le Ch atelier's principle?</h3>
Le Ch atelier's principle states that if the pressure is added in a nay reaction, then the equilibrium will be shifted toward the side where there are fewer atoms.
In this case, there are fewer moles on the left side.
Thus, when pressure is added, the equilibrium shift to the left side due to Le Ch atelier's principle.
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Deuterium also called heavy hydrogen, isotope of hydrogen with a nucleus consisting of one proton and one neutron, which is double the mass of the nucleus of ordinary hydrogen (one proton).
The deuterium atom is widely used in prototype fusion reactors.
From the information obtained by the problem-solving process, around 11 percentage of the school students need to have special diets.Hence, Option (C) i.e, 11 % is corrrect
<h3>What is problem-solving?</h3>
Identification of problems and marking out the steps and methods to solve them is regarded as problem-solving.
Problems can be identified only after attainment of information.
To be able to solve the problems of students suffering from a balanced diet, one out of every ten students need to include special diets in regular course.
Hence, option C holds true of the problem-solving process.
Therefore, Option (C) i.e, 11 % is corrrect
Learn more about problem-solving here ;
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