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3 years ago

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Arrange the slopes from flattest to steepest. -3/2, 0, 4/3, undefined

1 answer:

Dovator [93]3 years ago

8 0

To arrange the slopes we need to take their absolute values.
1. U<span>ndefined slope means a vertical line, so it is going to be steepest.
2.|4/3| = 4/3
3.|-3/2| = 3/2
4. 0 means horizontal line.

</span>From flattest to steepest: 0, -3/2, 4/3, undefined.

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Pls help me in this i really need help :( :)

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Hello and Good Morning/Afternoon:

<u>Let's take this problem step-by-step:</u>

<u>First off, let's write the line in point-slope form:</u>

$\rm \hookrightarrow (y-y_0)=m(x-x_0)$

(x₀, y₀) any random point on the line
'm' is the value of the slope

<u>Let's calculate the slope:</u>

$\rm \hookrightarrow Slope = \frac{y_2-y_1}{x_2-x_1}$

(x₁, y₁): any random point on the line ⇒ (-2, -6)
(x₂,y₂): any random point on the line that is not (x₁, y₁) ⇒ (2, -3)

$\rm \hookrightarrow slope = \frac{-3--6}{2--2} =\frac{3}{4}$

<u>Now that we found the slope, let's put it into the point-slope form</u>

⇒ we need (x₀, y₀) ⇒ let's use (2,-3)

$(y-(-3))=\frac{3}{4} (x-2)\\y+3=\frac{3}{4} (x-2)$

<u>The equation, however, could also be put into 'slope-intercept form'</u>

⇒ gotten by isolating the 'y' variable to the left

$y = \frac{3}{4}x-\frac{9}{2}$

<u>Answer:</u> $y = \frac{3}{4}x-\frac{9}{2}$ or $y+3=\frac{3}{4} (x-2)$

*<em>Either equations work, put the one that you are the most familiar with</em>

Hope that helps!

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