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SCORPION-xisa [38]
2 years ago
7

Sistema Decimal con ecuaciones lineles

Mathematics
1 answer:
VashaNatasha [74]2 years ago
8 0

The question is incomplete hence, I gave you a similar question that will enable you to understand how to treat Linear Equations with Decimals.

<h3>What is a Decimal system within Linear equations?</h3>

This is best exemplified by the example below:

\left\{ \begin{array}{cl}0.2x-0.3y = 1.3 \\0.5x + 0.2y= 2.3\end{array} \right.
e

Solution

Step 1 - Remove all decimals by multiplying equation 1 and 2 by 10. This gives us:

\left\{ \begin{array}{cl}2x-3y = 13 \\5x + 2y= 23\end{array} \right.


Now we have an equation without decimals.

Step 2 - we proceed to solve by elimination.

Assuming:

2x - 3y = 13 ............is  Equation 3; and

5x -2y = 23 ............. is Equation  4;

Lets multiply equation 3 by 2; and equation 4 by 3. This gives us

⇒ 4x - 6y = 26 ...............5

   15 x + 6y = 69..............6


step 3 - Add equation 5 and 6 to eliminate y.

4x - 6y = 26

<u> 15 x + 6y = 69
</u>19x = 95

solving for x

= 95/19

x = 5


Step 4 - Substitute x into any of the equations to find the value of Y


Using equation 5, we have:

4x - 6y = 26

⇒ 4(5) - 6y = 26

⇒ 20 - 6y = 26
⇒ -6y = 26-20
⇒ y = 6/-6

∴ y = -1

In summary, x = 5; y = -1


Learn more about Linear systems with decimals at:
brainly.com/question/10566339
#SPJ1



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h(2) = 7/4

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h(-2) = 11/(-8)

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Step-by-step explanation:

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h(-3) = {2*(-3)^2 - (-3) + 1} / {3*(-3) - 2}

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h(-2) = {2*(-2)^2 - (-2) + 1} / {3*(-2) - 2}

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h(-3) - h(-2) = (-2) - {11/(-8)}

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