An arithmetic sequence has t1 = 3, t2 = 10. Find tn, Sn.
1 answer:
Answer:
see explanation
Step-by-step explanation:
the n th term of an arithmetic sequence is
=
+ (n - 1)d
given
= 3 and
= 10, then
= 3 + d = 10 ⇒ d = 10 - 3 = 7
= 3 + 7(n - 1) = 3 + 7n - 7 = 7n - 4
the sum to n terms of an arithmetic sequence is
=
[2
+ (n - 1)d ]
=
[(2 × 3) + 7(n - 1) ]
=
(6 + 7n - 7 )
=
(7n - 1)
=
n² -
n
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Solve your inequality step-by-step.
7(x+4)>0
Simplify both sides of the inequality.
7x+28>0
Subtract 28 from both sides
.
7x+28−28>0−28
7x>−28
Divide both sides by 7.
7x/7 > −28/7
x > −4
Answer:
Step-by-step Solution:
<u>Isolate the variable x to get the answer.</u>
- x − 2/5 = −1
- => x = -1 + 2/5
- => x = -1 + 0.4
- => x = -0.6
Hence, the value of x is -0.6.
-2+2=0 because on the number line -2 is two spots from 0 then when u add a positive 2 it equals 0.
5.6 the answer is obviously