Answer:
see explanation
Step-by-step explanation:
Given the 2 equations
3x - 5y = - 2 → (1)
2x + y = 3 → (2)
Multiply (2) by 5 will eliminate y when added to (1), that is
10x + 5y = 15 → (3)
Add (1) and (3) term by term
(3x + 10x) + (- 5y + 5y) = (- 2 + 15)
13x = 13 ( divide both sides by 13 )
x = 1
Substitute x = 1 into (2) for corresponding value of y
2 + y = 3 ⇒ y = 3 - 2 = 1
Solution is (1, 1)
Answer:
x ≤ 2
Step-by-step explanation:
We are given the inequality:

First, get rid of the denominator by multiplying both sides by 2:

Add both sides by 6 then subtract both sides by x:

Then divide both sides by 3:

Therefore, the answer is x ≤ 2
Answer:
the residual is 0.2032
Step-by-step explanation:
The regression line has been given as:
Y^ = 0.00753X-0.06759
The paired observation for X is (31, 0.369)
The value of X is the empathy score under subject 15 = 31
The value of the brain activity under subject 15 is 0.369
So we have y^ = 0.00753(31) - 0.06759
= 0.1658
Then the residual = y - y^
= 0.369 - 0.1658
= 0.2032
Therefore the residual is 0.2032
Please check the attachment for the table, it will aid you in understanding the solution
Answer:
see explanation
Step-by-step explanation:
The product of 3 and x is 3x
Four more than this product is 3x + 4, thus
3x + 4 = 19 ← is the equation
Answer:
Yes, an arrow can be drawn from 10.3 so the relation is a function.
Step-by-step explanation:
Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.
The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.
In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.
However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.