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Scrat [10]
3 years ago
13

An arithmetic sequence has t1 = 3, t2 = 10. Find tn, Sn.

Mathematics
1 answer:
Softa [21]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

the n th term of an arithmetic sequence is

t_{n} = t_{1} + (n - 1)d

given t_{1} = 3 and t_{2} = 10, then

t_{2} = 3 + d = 10 ⇒ d = 10 - 3 = 7

t_{n} = 3 + 7(n - 1) = 3 + 7n - 7 = 7n - 4

the sum to n terms of an arithmetic sequence is

S_{n} = \frac{n}{2}[2t_{1} + (n - 1)d ]

                        = \frac{n}{2}[(2 × 3) + 7(n - 1) ]

                        = \frac{n}{2}(6 + 7n - 7 )

                        = \frac{n}{2}(7n - 1)

                        = \frac{7}{2} n² - \frac{1}{2} n



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Answer:

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Step-by-step explanation:

an = d (n - 1) + c

an = what you're looking for

n = term position

d = the common difference, in your case, 16

c = first term of the sequence, or -27

a₇₂ = 16(72 - 1) + -27 = 1109

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To convert a fraction to simplest form we need to find the greatest common factor. 

The fraction can not be simplified because it is already in simplest form but we can change it to a mixed fraction. 

         Steps to solve 

<span>1) Set up the long division.
</span>
<span>2) Calculate 13 ÷ 8, which is 1 with a remainder of 5.
</span>
3) Bring down 7, so that 57 is large enough to be divided by 8.

4) Calculate 57 ÷ 8, which is 7 with a remainder of 1.

<span>5) Bring down 7, so that 17 is large enough to be divided by 8.
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<span>6) Calculate 17 ÷ 8, which is 2 with a remainder of 1.
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<span>7) Therefore, 1377 ÷ 8 = 172 with a remainder of 1.
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