All categories

3 years ago

(4) need help and the answer

Mathematics

1 answer:

Oksi-84 [34.3K]3 years ago

3 0

OK well it would be A But then it would be C but A & C Are Wrong so it Would be D

You might be interested in

According to the last census (2010), the mean number of people per household in the United States is LaTeX: \mu = 2.58 Assume a

Veseljchak [2.6K]

Answer:

P(2.50 < Xbar < 2.66) = 0.046

Step-by-step explanation:

We are given that Population Mean, $\mu$ = 2.58 and Standard deviation, $\sigma$ = 0.75

Also, a random sample (n) of 110 households is taken.

Let Xbar = sample mean household size

The z score probability distribution for sample mean is give by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

So, probability that the sample mean household size is between 2.50 and 2.66 people = P(2.50 < Xbar < 2.66)

P(2.50 < Xbar < 2.66) = P(Xbar < 2.66) - P(Xbar $\leq$ 2.50)

P(Xbar < 2.66) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{2.66-2.78}{\frac{0.75}{\sqrt{110} } }$ ) = P(Z < -1.68) = 1 - P(Z 1.68)

= 1 - 0.95352 = 0.04648

P(Xbar $\leq$ 2.50) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{2.50-2.78}{\frac{0.75}{\sqrt{110} } }$ ) = P(Z $\leq$ -3.92) = 1 - P(Z < 3.92)

= 1 - 0.99996 = 0.00004

Therefore, P(2.50 < Xbar < 2.66) = 0.04648 - 0.00004 = 0.046

7 0

3 years ago

WILL GIVE BRAINLIEST!!!!

Firdavs [7]

126 I hope that this is correct answer

3 0

3 years ago

Suppose that the number of cars manufactured at an automobile plant varies Jointly as the number of workers and the time they wo

12345 [234]

Answer:

It takes 33 hours to produce 66 cars.

Step-by-step explanation:

When dividing 220 workers buy the amount of cars produced the amount of time spent on making 66 cars is 33 hours.

Easier Explaination:

Divide the amount of workers to the cars produced to find out how many hours it takes.

7 0

3 years ago

(4y 2 – 5y) + (3y – 7y 2) – (2y 2 + 6y – 5) Simplify.

Elan Coil [88]

Equation at the end of step 1 : (((4•(y2))-5y)+(3y-(7•(y2))))-((2y2+6y)-5) Step 2 :Equation at the end of step 2 : (((4•(y2))-5y)+(3y-7y2))-(2y2+6y-5) Step 3 :Equation at the end of step 3 : ((22y2 - 5y) + (3y - 7y2)) - (2y2 + 6y - 5) Step 4 : Step 5 :Pulling out like terms :

5.1 Pull out like factors :

 -5y2 - 8y + 5 = -1 • (5y2 + 8y - 5)

I hope tht help

4 0

3 years ago

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of

Lilit [14]

Check the picture below.

$\bf (\stackrel{a}{1}~,~\stackrel{b}{-1})\qquad \impliedby \textit{let's find the hypotenuse} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c = \sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{1^2+(-1)^2}\implies c=\sqrt{2} \\\\[-0.35em] ~\dotfill$

$\bf sin(\theta ) \implies \cfrac{\stackrel{opposite}{-1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{-1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies -\cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies -\cfrac{\sqrt{2}}{2}$

$\bf cos(\theta ) \implies \cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies \cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies \cfrac{\sqrt{2}}{2} \\\\\\ tan(\theta ) = \cfrac{\stackrel{opposite}{-1}}{\stackrel{adjacent}{1}}\implies tan(\theta ) = -1$

7 0

3 years ago

Read 2 more answers