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Ber [7]
3 years ago
14

(4) need help and the answer

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
3 0
OK well it would be A But then it would be C but A & C Are Wrong so it Would be D

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What does this equal
docker41 [41]

Answer:

I think it is 9

Step-by-step explanation:

3×3 is 9 + 15= 24÷4=3×3=9

8 0
4 years ago
On a map, the scale shown is 1 inch : 5 miles. If a wildlife refuge is 50 square miles, what is the area of the refuge on the ma
Mama L [17]

Answer:

dababy

Step-by-step explanation:

lets go

8 0
3 years ago
At beacon hills middle school, 10% of children travel by bus. if this represents 60 cgildren how many children attend to the sch
VMariaS [17]
600,, because if 10% is 60 all you have to do is multiply 60 times 10 to get your answer on how many children attend the middle school. 20%= 120,, 30%= 180,, 40%= 240 and so on.
5 0
4 years ago
Question 7: Which of the following statements is true?
yawa3891 [41]

Problem 7)

The answer is choice B. Only graph 2 contains an Euler circuit.

-----------------

To have a Euler circuit, each vertex must have an even number of paths connecting to it. This does not happen with graph 1 since vertex A and vertex D have an odd number of vertices (3 each). The odd vertex count makes it impossible to travel back to the starting point, while making sure to only use each edge one time only.

With graph 2, each vertex has exactly two edges attached to it. So an Euler circuit is possible here.

================================================

Problem 8)

The answer is choice B) 5

-----------------

Work Shown:

abc base 2 = (a*2^2 + b*2^1 + c*2^0) base 10

101 base 2 = (1*2^2 + 0*2^1 + 1*2^0) base 10

101 base 2 = (1*4 + 0*2 + 1*1) base 10

101 base 2 = (4 + 0 + 1) base 10

101 base 2 = 5 base 10


4 0
3 years ago
Shown here are four frequency distributions. Each is incorrectly constructed. State the reason why.
Tanya [424]

Answer/Step-by-step explanation:

a. The the class width for the 1st, 2nd, 3rd, and 5th row equal 5 in the frequency distribution. Whereas, in the 4th row, the class width is 4 (49 - 45). This makes the construction incorrect.

b. Here, the upper limit of each consecutive class was used as the lower limit if the next class. For example, 9 is a member of the first class, which is the upper limit if the class in the first row, it ought not to be included as a member of the next class in the second row.

c. In the 3rd row, the lower limit of the class should be 133, NOT 138.

d. Different class width were used.

Row 1 class width = 13 - 9 = 4

Row 2 class width = 19 - 14 = 5

Row 3 class width = 25 - 20 = 5

Row 4 class width = 28 - 26 = 2

Row 5 class width = 32 - 29 = 3

8 0
3 years ago
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