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igomit [66]
3 years ago
9

Zoom in to see wha the question is asking please help

Mathematics
1 answer:
garik1379 [7]3 years ago
8 0

Answer:

The median age of the players on Team A is <u>less than</u> the median age of the players on B.

  • Count to the middle number on each. Median(A) = 18, Median(B) = 19.

The mean age of the players on Team A is <u>less than</u> the mean age of the players on B.

  • The mean is the average. Mean(A) = 394/22 = 17.9, Mean(B) = 413/22 = 18.7

The IQR for the age of the players on Team A is <u>less than</u> the IQR for the age of the players on B.

  • Take the median of the upper half, and the median of the lower half.
  • Q1(A) = 17, Q1(B) = 16.
  • Q3(A) = 19, Q3(B) = 21.
  • IQR(A) = 19-17 = 2, IQR(B) = 5.

The first quartile of players' age on Team A is <u>greater than</u> the first quartile of players' age on Team B.

  • Q1(A) = 17, Q1(B) = 16.
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