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1 answer:
Answer:
The median age of the players on Team A is <u>less than</u> the median age of the players on B.
Count to the middle number on each. Median(A) = 18, Median(B) = 19. The mean age of the players on Team A is <u>less than</u> the mean age of the players on B.
The mean is the average. Mean(A) = 394/22 = 17.9, Mean(B) = 413/22 = 18.7 The IQR for the age of the players on Team A is <u>less than</u> the IQR for the age of the players on B.
Take the median of the upper half, and the median of the lower half. Q1(A) = 17, Q1(B) = 16. Q3(A) = 19, Q3(B) = 21. IQR(A) = 19-17 = 2, IQR(B) = 5. The first quartile of players' age on Team A is <u>greater than</u> the first quartile of players' age on Team B.
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I think the answer is D, None of the above
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Answer:
I think it is 6/1
Step-by-step explanation:
You are wrong because 0.167 into a fraction is 167/1000 and that isn't one of the options but when I did it 1 1/2=3/2=1.5 and 1/4=0.25 so I did 1.5 divide by 0.25 and it gave me 6 so that why I think that my answer is correct and yours is not.
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