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igomit [66]
3 years ago
9

Zoom in to see wha the question is asking please help

Mathematics
1 answer:
garik1379 [7]3 years ago
8 0

Answer:

The median age of the players on Team A is <u>less than</u> the median age of the players on B.

  • Count to the middle number on each. Median(A) = 18, Median(B) = 19.

The mean age of the players on Team A is <u>less than</u> the mean age of the players on B.

  • The mean is the average. Mean(A) = 394/22 = 17.9, Mean(B) = 413/22 = 18.7

The IQR for the age of the players on Team A is <u>less than</u> the IQR for the age of the players on B.

  • Take the median of the upper half, and the median of the lower half.
  • Q1(A) = 17, Q1(B) = 16.
  • Q3(A) = 19, Q3(B) = 21.
  • IQR(A) = 19-17 = 2, IQR(B) = 5.

The first quartile of players' age on Team A is <u>greater than</u> the first quartile of players' age on Team B.

  • Q1(A) = 17, Q1(B) = 16.
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Answer: approximately 5148 feet directly north of point A

This is equivalent to 0.975 miles

==============================================================

Explanation:

Check out figure 1 (attached image below) to see how the drawing is set up.

Points A and B are separated by 2 miles, or 10560 feet. Use the conversion factor 1 mile = 5280 feet.

Because sound travels at roughly 1100 feet per second (assuming all of the conditions are right), this means that after x seconds, the sound wave has traveled a total distance of 1100x feet. This is the distance from A to C. Point C is the firework location.

The distance from B to C is 1100(x+6) feet because it takes 6 more seconds for the soundwave to travel from C to B, compared from C to A.

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See figure 2 in the attached images to see the steps on solving for x. The numbers get quite big, though in the end x is fairly small. We end up with x = 4.68, which is approximate due to the 1100 figure being approximate.

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