Zoom in to see wha the question is asking please help
1 answer:
Answer:
The median age of the players on Team A is <u>less than</u> the median age of the players on B.
- Count to the middle number on each. Median(A) = 18, Median(B) = 19.
The mean age of the players on Team A is <u>less than</u> the mean age of the players on B.
- The mean is the average. Mean(A) = 394/22 = 17.9, Mean(B) = 413/22 = 18.7
The IQR for the age of the players on Team A is <u>less than</u> the IQR for the age of the players on B.
- Take the median of the upper half, and the median of the lower half.
- Q1(A) = 17, Q1(B) = 16.
- Q3(A) = 19, Q3(B) = 21.
- IQR(A) = 19-17 = 2, IQR(B) = 5.
The first quartile of players' age on Team A is <u>greater than</u> the first quartile of players' age on Team B.
You might be interested in
There are 50 more dairy cattle than beef cattle.
Answer:
2y +10 +3y-4
5y+6
Step-by-step explanation:
Answer:A
Step-by-step explanation:
Answer:
80
Step-by-step explanation:
Since the problem already gives you the function, you only have to substitute the information
p= number of people = 4
C(p)= 20p
C(4)=20(4)
C(4)= 80
So the cost of admission for four people is $80.
Answer:
yes it does represent a function.
Step-by-step explanation: