3 years ago

The length of a rectangle is nine more than tripled the width if the perimeter is 146 inches find the dimensions

Mathematics

1 answer:

alexandr1967 [171]3 years ago

3 0

So here is the answer write it in your copy. thank you.

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let S be a square, let M and N be the midpoints of two adjacent sides, and let V be the corner of the square that is opposite bo

denis23 [38]

If we have a basis of 2 units for the length of the side of the square,
then MV = NV = 1

Using pythagoeran theorem
MN = sqrt (MV^2 + NV^2)
MN = sqrt(2)

Therefore,
sin θ = 1 /√2
or
sin θ = √2 / 2

5 0

3 years ago

Clark made four of his truck payments late and was fined four late fees. The total change to his savings from late fees was-$40.

luda_lava [24]

You would do 40 ÷ 4 which would be 10. so it was $10 per late fee

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3 years ago

Please help me solve this

Leokris [45]

D is the answer I think

5 0

4 years ago

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The area of a rectangle field is 4424 m squared. If the width of the field is 56 m, what is its length?

Wewaii [24]

We can divide 4424 by 56 to find our length. 4424/56 is 79. Therefore, the length is 79m. To check our answer, we can multiply 79*56. 79*56 is 4,424.

6 0

3 years ago

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Find the coordinates of the midpoint of HX. H(5.5, -4.75) and X(3.75, -2.75)

MAXImum [283]

( 4.625, - 3.75 )

the midpoint of (x₁, y₁ ) and (x₂, y₂ ) is

[ $\frac{1}{2}$ (x₁ + x₂ ), $\frac{1}{2}$ (y₁ + y₂ ) ]

here (x₁, y₁ ) = (5.5, - 4.75 ) and (x₂, y₂ ) = (3.75, - 2.75 )

[ $\frac{1}{2}$ (5.5 + 3.75 ), $\frac{1}{2}$ (- 4.75 - 2.75 ) ]

= (4.625, - 3.75 ) ← midpoint of HX

8 0

4 years ago