Answer:
Yes
Step-by-step explanation:
Because the circle is divided into 4 parts, and 3 out of 4 of the parts are shaded.
I would think A because regular quadrilaterals have 90-degree angles.
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
N is an odd integer
The Next Larger is N+2
N+2 + 2N = -27 + 4N
3N + 2 = 4N - 27
0 = 4N - 27 - 3N - 2
0 = N - 29
N = 29
They are 29 and 31.
31 + 2(29) = 4(29) - 27
31 + 58 = 89 = 116 - 27 yes it works
The answer should be X>4
Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :
2*x+8-(5*x-4)<0
Step by step solution :
Step 1 :
Pulling out like terms :
1.1 Pull out like factors :
-3x + 12 = -3 • (x - 4)
Equation at the end of step 1 :
Step 2 :
2.1 Divide both sides by -3
Remember to flip the inequality sign:
Solve Basic Inequality :
2.2 Add 4 to both sides
x > 4
