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Elanso [62]
3 years ago
5

Ben had 10 football jerseys. After his birthday, he increased his collection by 4 jerseys. Caleb, bens best friend had 6 jersey

before his birthday. If Caleb only recurved 2 jerseys for his birthday, will his percent increase be the same as bens
Mathematics
1 answer:
finlep [7]3 years ago
3 0

Answer:no

Step-by-step explanation:

Because if he got 2 and the other boy got 4 then the other boy had 2 more that he did

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There were 18 grey wolves after three years there were 27 grey wolves what is the percent increase
goldfiish [28.3K]
27-18= 9
9/18 x100= 50
There was a 50% increase in grey wolves
3 0
3 years ago
The mass, m grams, of a radioactive substance, present at time t days after first being observed, is given by the formula m=24e^
Reika [66]

Answer:

(i) The value of<em> m</em> when t = 30 is 13.2

(ii) The value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) The rate of the mass when t=50 is -0.18            

Step-by-step explanation:

(i) The <em>m</em> value when t = 30 is:

m = 24e^{-0.02t} = 24e^{-0.02*30} = 13.2

Then, the value of<em> m</em> when t = 30 is 13.2

(ii) The value of the mass when t=0 is:

m_{0} = 24e^{-0.02t} = 24e^{-0.02*0} = 24    

Now, the value of <em>t </em>is:

ln(\frac{m_{0}/2}{24}) = -0.02t

t = -\frac{ln(\frac{24}{2*24})}{0.02} = 34.7

Hence, the value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) Finally, the rate at which the mass is decreasing when t=50 is:

\frac{dm}{dt} = \frac{d}{dt}(24e^{-0.02t}) = 24(e^{-0.02t})*(-0.02) = -0.48*                            (e^{-0.02*50}) = -0.18

Therefore, the rate of the mass when t=50 is -0.18.

I hope it helps you!                  

3 0
2 years ago
Fractions with the same numerical value;fractions are equal to eachother are ?
vova2212 [387]
Equivalent. Fractions that are equal are equivalent.
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8 0
3 years ago
HELP WITH THIS QUESTION???
schepotkina [342]

❇Answer: y=-5x+5

❇Explanation:

First I'll write down the points given:

(-2,15)➡1st point=(x1,y1)

(2,-5)➡ 2nd point=(x2,y2)

(6,-25)➡ 3rd point=(x3,y3)

(10,-45)➡4th point=(x4,y4)

Calculating slope using 1st and 2nd points:

slope= (y2-y1)/(x2-x1)

=(-5-15)/[2-(-2)]

=-20/4

=-5

Calculating slope using 3rd and 4th points:

slope= (y4-y3)/(x4-x3)

=[-45-(-25)]/(10-6)

=-20/4

=-5

Since slope of first two points and last two points are equal, all of these points lie on same line whose equation can be given in slope-intercept form as,

↪y=mx+c {m is slope}

↪y=-5x+c➡Eqn(1)

Let (0,c) be any point cutting y-axis making

y-intercept=c

Lets take 1st point and (0,c) and apply slope formula,

slope=(c-15)/[0-(-2)]

↪-5=(c-15)/2

↪c-15=-10

↪c=15-10

↪c=5

Put value of c in Eqn(1),

↪y=-5x+5

7 0
3 years ago
10 points :)
elixir [45]

Answer:

No invariant point

Step-by-step explanation:

Yo!

When we translate a form, in this case a polygon We must observe the direction of the vector. Since our vector is:

1) Let's apply  that translation to this polygon, a square. Check it below:

2) The invariant points are the points that didn't change after the transformation, simply put the points that haven't changed.

Examining the graph, we can see that no, there is not an  invariant point, after the translation. There is no common point that belongs to OABC and O'A'B'C' simultaneously. All points moved.

I hope you understood !

7 0
3 years ago
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