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Elanso [62]
2 years ago
6

Solving a word problem using a two-step med

Mathematics
1 answer:
stepladder [879]2 years ago
5 0

Inequality is 6t  ≤ 44 and Jim can rent a boat for 7.33 hrs or less

<u> Solution:</u>

Given that  

Maximum amount Jim can spend to rent a boat = $34

Rental cost of boat for 1 hour = $6

Also Jim has a discount coupon for $8 off.

Need to determine possible number of hours Jim could rent a boat.

Let’s assume possible number of hours Jim could rent a boat be represented by variable "t"

Cost of renting boat for 1 hour = 6

So Cost of renting a boat for t hours = t x renting boat for 1 hour = t x 6 = 6t

Also Maximum amount Jim can spend to rent a boat = $34

As Jim has a discount coupon for $8 off, so Total amount Jim can spend to rent a boat = $ 34 + $ 8 = $ 44

So cost of renting a boat for t hours must be less that of equal to Total amount Jim can spend to rent a boat

=> 6t  ≤ 44

On solving above equality for "t" we get ,

\begin{array}{l}{t \leq \frac{44}{6}} \\\\ {=>\mathrm{t} \leq 7.3333 \mathrm{hrs}}\end{array}

Hence inequality is  6t  ≤ 44 and Jim can rent a boat for 7.33 hrs or less.

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Answer:

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Step-by-step explanation:

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2/5 will be the answer
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pochemuha
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where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan. 

We require B(n) = 0...i.e. balance of 0 after n months. 

so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1] 

Then, with some algebraic juggling we get: 

n = -[log(1 - (Ai/P)]/log(1 + i) 

Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43 

Also, i = (13.6/100)/12 => 0.136/12 per month 

i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12) 

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b) Now we have A = $754.43 - $300 = $454.43 so, 

n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12) 

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3 years ago
An aquarium measures 11 feet wide, 10 feet long and 7 feet deep. Approximately how many gallons of water does it hold if there a
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Answer:

Please check explanation

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We shall be matching the given statements with the features we have on the graph

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We can see that the graph rose from 8am before it finally comes to zero at 8pm

Positive or negative interval matches with it was getting warmer between 2am and 2pm.

While temperature was lowest at 2am, we can see a peak at 2pm.

8 0
3 years ago
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