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Natali [406]
3 years ago
12

Carrie started work at 8 a.m. and left at 1:30 p.m. How many hours of work should she record on her time card for the day?

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
5 0
Start:  8 a. m.
Finish:  1 : 30 p.m. = 13 hours 30 minutes
13 h 30 min - 8 h = 5 h 30 min
She should record 5 hours and 30 minutes on her time card for the day.
Aloiza [94]3 years ago
4 0
5 hours 30 minutes if im right
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What is the maximum volume of a square pyramid that can fit inside a cube with a side length of 14 cm?
sukhopar [10]

Answer:

Step-by-step explanation:

Pyramid height should be 14

Base area should be 14*14(196)

So, Base area is 196

1. Multiply the Base area by the height of the pyramid:

196*14=2744

2. Divide the number above by 3:

2744/3=914.7

7 0
2 years ago
Suppose the horses in a large stable have a mean weight of 1467lbs, and a standard deviation of 93lbs. What is the probability t
krok68 [10]

Answer:

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 1467, \sigma = 93, n = 49, s = \frac{93}{\sqrt{49}} = 13.2857

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable?

This is the pvalue of Z when X = 1467 + 9 = 1476 subtracted by the pvalue of Z when X = 1467 - 9 = 1458.

X = 1476

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1476 - 1467}{13.2857}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 1458

Z = \frac{X - \mu}{s}

Z = \frac{1458 - 1467}{13.2857}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

5 0
3 years ago
A car travels at a speed of 25 miles per hour for t hours
Pepsi [2]

Answer: 25t+45m

Step-by-step explanation:

Really simple because if they traveled 25mi/h for t hours, that makes it 25t miles. They traveled 45mi/h for m hours so it's 45m. If you add them together, 25t+45m.

If this helped, brainliest please.

4 0
2 years ago
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