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Talja [164]
3 years ago
12

Two masses are joined by a mass less string. A 33-N force applied vertically to the upper mass gives the system a constant upwar

d acceleration of 3.5 m/s². If the string tension is 16 N, what are the two masses?
Physics
1 answer:
lisov135 [29]3 years ago
7 0

Lower mass: 1.20 kg, upper mass: 1.28 kg

Explanation:

In order to solve the problem, we consider the forces acting on the upper mass only first.

The upper mass is acted upon three forces:

  • The applied force F_a=33 N, upward
  • The weight of the mass itself, m_u g, where m_u is the upper mass and g=9.8 m/s^2 is the acceleration of gravity, downward
  • The tension in the string, T=16 N, downward

Therefore, the equation of the forces for the upper mass is:

F_a - m_u g - T = m_u a

where

a=3.5 m/s^2 is the acceleration (upward)

Solving for m_u,

m_u = \frac{F_a-T}{a+g}=\frac{33-16}{3.5+9.8}=1.28 kg

Now we can find the lower mass by considering the forces acting on it:

  • The tension in the string, T = 16 N, upward
  • The weight of the mass itself, m_L g, where m_L is the lower mass, downward

So the equation of the forces is

T-m_L g = m_L a

And solving for the mass,

m_L = \frac{T}{a+g}=\frac{16}{3.5+9.8}=1.20 kg

Learn more about acceleration and forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

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A fairground ride consists of a large vertical drum that spins so
expeople1 [14]

Answer:

v = 3.84 m/s

Explanation:

In order for the riders to stay pinned against the inside of the drum the frictional force on them must be equal to the centripetal force:

Centripetal\ Force = Frictional\ Force\\\\\frac{mv^2}{r} = \mu R = \mu W\\\\\frac{mv^2}{r} = \mu mg\\\\\frac{v^2}{r} = \mu g\\\\v = \sqrt{\mu gr}

where,

v = minimum speed = ?

g = acceleration due to gravity = 9.81 m/s²

r = radius = 10 m

μ = coefficient of friction = 0.15

Therefore,

v=\sqrt{(0.15)(9.81\ m/s^2)(10\ m)}

<u>v = 3.84 m/s</u>

6 0
3 years ago
Do noble gases lose or gain electrons to get a full valence shell?
alexdok [17]
They don't lose OR gain electrons as they've already achieved the octet rule and have 8 valence electronsn
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3 years ago
Suppose Mary would like to design an emergency overheating alarm using one of these materials. In her design, at room temperatur
Reptile [31]

Answer:

A. 92.88 °C

B. 401.535 °C

Explanation:

So, the overheating system is going to be based on the principle of thermal linear expansion. The behavior of this principle is ruled by the equation:

∆L= L_i * ∆T * α  

Where α is a coefficient of linear expansion. For a cylinder made from polycarbonate α = 70,2*10^(-6)  °C^(-1) and for a cylinder made from cast iron α = 12*10^(-6)  °C^(-1). If we isolate the term of the temperature’s difference, we have:

∆L/(L_i * α) = ∆T → T_f = T_i + ∆L/(L_i * α)

Replacing the values, for the case of the Polycarbonate we have:

T_f = T_i + ∆L/(L_i * α) = 23°C+0,0273cm/(6,01cm *70,2 * 10^(-6)°C^(-1) ) = 92,88 °C

Replacing the values, for the case of the Cast Iron we have:

T_f = T_i +∆L/(L_i * α) = 23°C + 0,0273cm/(6,01cm * 12 * 10^(-6) °C^(-1) ) = 401,535 °C

As we see, is way better to use the polycarbonate in this application.

Have a nice day. Let me know if I can help you with anything else. :D

4 0
3 years ago
A wheel of radius 30 cm is rotating at a rate of 2.0 revolutions every 0.080 s. (A) through what angle, in radians, does the whe
ioda

You said 2 revolutions every 0.08 seconds

1 revolution = 2pi radians.

A). The 'unit rate' is    (2 rev) x (2pi / 0.08 sec)  = 50pi radians/sec. =

                                                       157.1 radians per sec (rounded)

B). Radius of the wheel = 30 cm
     Circumference = 2pi R = 60pi cm = 188.5 cm (rounded)

     Rotation speed = 2 revs per 0.08 sec
     Linear speed =    2 x 60pi cm per 0.08 sec

                               (120pi cm) / (0.08 sec) = 47.12 meters per sec

C). Frequency = (revs) per second

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A wise decision. Boston is a good place to be ... from.
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