Answer:
Different street blocks are different lengths, so it won't be possible to answer this.
Earth around the sun and the moon around the earth
A) Using:
2as = v² - u², where v will be 0 at max height
s = -(160)² / 2 x -32.174
s = 397.8 ft
b) Using:
s = ut + 1/2 at²
256 = 160t - 16.1t²
solving for t,
t = 2.0, t = 7.9
Now, v = u + at, for both times:
v(2) = 160 - 32.174(2)
v(2) = 95.7 ft/sec on the way up
v(7.9) = 160 - 32.174(7.9)
v(7.9) = -94.3 ft/sec; 94.3 ft/sec on the way down
c) -32.174 ft/s², which is the acceleration due to gravity.
d) s = 0
0 = 160t - 1/2 x 32.174t²
t = 9.94 seconds
Answer:
<em>The horizontal component of the velocity is 49.85 m/s.</em>
Explanation:
<u>Rectangular Components of a Vector</u>
A 2D vector can be expressed in several forms. The rectangular form gives its two components, one for each axis (x,y). The polar form gives the components as the pair (r,θ) being r the magnitude and θ the angle.
When the magnitude and angle of the vector are given, the rectangular components are calculated as follows:


Where v is the magnitude of the vector and θ is the angle with respect to the x positive direction.
The cart is moving at v=55 m/s at θ=25°, thus:


The horizontal component of the velocity is 49.85 m/s.
Answer:
(a). The rotational inertia is 
(b). The magnitude of the magnetic torque is 
Explanation:
Given that,
Mass of neutron 
Density of neutron 
(a). We need to calculate the rotational inertia
Using formula of rotational inertia for sphere
...(I)
We know that,

Put the value of volume


Put the value of R in equation (I)

Put the value into the formula


The rotational inertia is
.
(b). We need to calculate the magnitude of the magnetic torque
Using formula of torque

Put the value into the formula


The magnitude of the magnetic torque is 
Hence, (a). The rotational inertia is 
(b). The magnitude of the magnetic torque is 