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3 years ago

What are the apparent zeros of the function graphed above. (-0.7, -2,7)

Mathematics

2 answers:

Black_prince [1.1K]3 years ago

4 0

Answer:

The zero of the function on the range (-0.7,-2.7) is {-2}

Step-by-step explanation:

The zeros of a function can be determined graphically and are the points where the graph intercepts the x-axis, that is, where the value of y is zero.

In this case we can see that the three points where the graph cuts to the x-axis are {-2,1,4}.

However if we evaluate the zeros of the function in the range writen on your question, the zero of the function in the range (-0.7, -2.7) would be only the number {-2}

castortr0y [4]3 years ago

3 0

Answer:

x ∈ {-2, 1, 4}

Step-by-step explanation:

The graph shows y = 0 when x = -2 or 1 or 4. Hence these values of x are the zeros of the function.

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3 years ago

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White raven [17]

Answer:

the percentage is 12%

Step-by-step explanation:

Given that

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

(a) Complete the table of values for y- 2x + 5 - 0 1 2 1 5 Y

maxonik [38]

Answer:

Step-by-step explanation:

I think you meant y = -2x + 5.

x y = -2x + 5

0 5

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2 years ago

The marginal profit in dollars on Brie cheese sold at a cheese store is given by Upper P prime (x )equals x (60 x squared plus 9

blondinia [14]

Answer:

Part A:

P(x)=15x^4+30x^3-50

Part B:

P(4)=$4270

Step-by-step explanation:

Part A:

In order to find the profit function P(x) we have to integrate the P'(x)

P'(x)=x(60x^2+90x)

P'(x)=60x^3+90x^2

$\int\limits {p'(x)} \, dx =\int\limits {60x^3+90x^2} \, dx$

P(x)=15x^4+30x^3+C

when x=0, C=-50

P(x)=15x^4+30x^3-50

Part B:

x=4

P(x)=15x^4+30x^3-50

P(4)=15*4^4+30*4^3-50

P(4)=$4270

Profit from selling 400 pounds is $4270

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3 years ago