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Scilla [17]
2 years ago
10

Work out the total surface area of this hemisphere which has a radius of 8cm.

Mathematics
1 answer:
Masja [62]2 years ago
4 0

\bf \textit{surface area of a sphere}\\\\ SA=4\pi r^2~~ \begin{cases} r=radius\\ \cline{1-1} r=8 \end{cases}\implies SA=4\pi (8)^2\implies SA=256\pi \\\\\\ \stackrel{\textit{half of that for a \underline{hemi}sphere}}{\cfrac{256\pi }{2}\implies 128\pi \implies }\stackrel{\textit{rounded up}}{402.1}

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3 years ago
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I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
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In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0    and    (y - 9) = 0
Now you're y² + 1 will equal:
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y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
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So you're final answer should be y = i and 9
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