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4 years ago

P divided by 6 as an algebraic expressions

1 answer:

5 0

<span>The algebraic expression that would show the "p divided by 6" is a fraction which shows the dividend, p, as the numerator and the divisor, 6, as the denominator. In symbols, this can be written as follows: p/6</span>

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Please answer ASAP and if you do you will get Brainliest. Catherine buys a gallon of ice cream from the store. After taking it h

rodikova [14]

Answer:

Catherine's sister ate 2/15 gallons of the ice cream.

$\displaystyle \frac{2}{15}$ .

Step-by-step explanation:

Let $x$ be the amount of ice cream that Catherine's sister ate, in gallons.

Original amount: 1 gallon.

What Catherine ate: $\displaystyle \frac{1}{5}$ gallons.
What Catherine's sister ate is assumed to be $x$ gallons.

What's left: $\displaystyle \frac{2}{3}$ gallons.

Consider the relationship:

$\text{Original amount - What Catherine ate - What Catherine's Sister ate}\\ =\text{ What's left.}$ .

That is:

$\displaystyle 1- \frac{1}{5} - x = \frac{2}{3}$ .

Add $x$ to both sides of this equation:

$\displaystyle 1 - \frac{1}{5} = \frac{2}{3} +x$

Substract $\displaystyle \frac{2}{3}$ from both sides:

$\displaystyle 1 - \frac{1}{5} - \frac{2}{3} = x$ .

Convert the denominator of all three numbers on the left-hand side to $3 \times 5 = 15$

$\displaystyle \frac{15}{15} - \frac{3}{15} - \frac{10}{15} = x$ .

$\displaystyle x = \frac{2}{15}$ .

In other words, Catherine's sister ate $\displaystyle \frac{2}{15}$ gallons of the ice cream.

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yulyashka [42]

16 is the correct answer I believe because the double negative is canceled out.

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3 years ago

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The answer is 14.63 i hope this helps you

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3 years ago

If a polynomial function f(x) has roots 4 – 13i and 5, what must be a factor of f(x)?

Morgarella [4.7K]

The factor of f(x) is (x-(4-13i))

If a polynomial function f(x) has roots 4 – 13i and 5

One of the complex roots is 4-13i

If we have one complex root then there should be one more complex root.

<h3>What is the complex root?</h3>

complex roots come in pairs like (a+ib) and (a-ib)

so another complex root for 4-13i is 4+13i

If 'a' is a root then the factor is (x-a)

4+13i is a root

So the factor is (x-(4-13i))