P divided by 6 as an algebraic expressions

1 answer:

5 0

<span>The algebraic expression that would show the "p divided by 6" is a fraction which shows the dividend, p, as the numerator and the divisor, 6, as the denominator. In symbols, this can be written as follows: p/6</span>

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How to round to nearest hundredth

loris [4]

Answer:

just look at the decimal after the decimal number is the tenths place the hundreds place and so on if i have to round 567.1092 i would round the nine up to make the zero a one so my rounded answer would be 567.11

Step-by-step explanation:

4 0

3 years ago

Please help me im about to fail!!!! Express your answer in scientific notation.

Illusion [34]

Answer:

3.74 x 10^5

Step-by-step explanation:

First expand the term in scientific notation into normal notation.

3.3 x 10^5 - Here the ^5 tells us to move the decimal five places to the right, so we go from

3.30000 to

330000.00

So 3.3 x 10^5 = 330,000

Now add that to 44,000 and you get 374,000.

Return this number to scientific notation. Move the decimal back to its spot before the 3. We go from

374,000.00 to

3.74000

Once again the decimal has moved five places, so that is the number in the exponent of the our scientific notation, and therefore our answer is

3.74 x 10^5

3 0

3 years ago

Which of these places rounds 43,754 to the lowest number?

scoundrel [369]

The tens is the lowest

8 0

3 years ago

Which expression is equivalent to ( 4mn / m^-2n^6)^-2a. n^6 / 16m^8b. n^10 / 16m^6c. n^10 / 8m^8d. 4m^3 / n^8?

Eva8 [605]

$\huge{(} \small{\frac{4mn}{ {m}^{ - 2} {n}^{6} }} \huge{) } \small{{}^{ {}^{ {}^{ {}^{ - 2} } } } }\\ \\ \\ \huge{(} \small{ \frac{4 \times m {}^{1} \times n {}^{1} }{ {m}^{ - 2} \times {n}^{6} }} \huge{)} \small{^{ {}^{ {}^{ {}^{ - 2} } } }} \\ \\ \\ \huge{(} \small{4 \times {m}^{1 - ( - 2)} \times {n}^{1 - 6}} \huge{)} \small{ {}^{ {}^{ {}^{ {}^{ - 2} } } } } \\ \\ \\ \huge{(} \small{ 4 \times {m}^{1 + 2} \times {n}^{ - 5} } \huge{)} \small{ { }^{ {}^{ {}^{ {}^{ - 2} } } } } \\ \\ \\ \small{ {(4)}^{ - 2} \times ({m}^{3} ) ^{ - 2} \times {(n{}^{ - 5} )}^{ - 2} } \\ \\ \\ \frac{1}{ {4}^{2} } \times {m}^{ - 6} \times {n}^{ 10} \\ \\ \\ \frac{1}{16} \times \frac{1}{ {m}^{6} } \times {n}^{10} \\ \\ \\ \frac{ {n}^{10} }{16{m}^{6} }$

$\text{ Hence, option B is correct }$

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4 years ago

G C D of 130 and 150

wlad13 [49]

Answer:

GCF = 10

Step-by-step explanation:

8 0

3 years ago