To solve this problem you must apply the proccedure shown below:
1. You have that the <span>parabola is 12 meters high at the vertex and at a height of 10 meters, the width is 8 meter.
2. Therefore, you have:
x^2=-4a(y^2-k)
4</span>^2=-4a(10-12)
16=-40a+48
16=8a
a=16/8
a=2
y=0
x^2=-8(0-12)
x^2=96
x=√96
x=9.79x2
x=19.58
3. Therefore, as you can see, the answer is: 19.58 meters.<span>
</span>
Answer:
a is equilateral and right, b is scalene and acute, c is equilateral and acute, d is isoseles and right, e is scalene and either acute or right, f is equilateral and acute, g is scalene and acute, and h is scalene and obtuse
Step-by-step explanation:
Answer:
<h2>
x² + 9 + 6x </h2>
Step-by-step explanation:
expand and simplify (x+3)²
(x+3)² =
x² + 9 + 2 × x × 3 =
x² + 9 + 6x
<u>Solution </u><u>1</u><u> </u><u>:</u><u>-</u>
Given expression ,
We know that, ![a^{\frac{m}{n}} = \sqrt[n]{a^m}](https://tex.z-dn.net/?f=%20a%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%5Em%7D%20)
Therefore , this can be written as ,
![\implies \sqrt[4]{13^3}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%5B4%5D%7B13%5E3%7D%20)
<u>Solution</u><u> </u><u>2</u><u>:</u><u>-</u>
Given expression ,
![\implies \sqrt[3]{24^{10}}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%5B3%5D%7B24%5E%7B10%7D%7D%20)
We know that,
Therefore, this can be written as ,
