All categories

2 years ago

How to tell if a quadratic equation has a real solution?

Mathematics

2 answers:

Dennis_Churaev [7]2 years ago

7 0

The easiest way to determine if a quadratic equation has real solutions is by using the discriminant.

Start by finding a,b and c. You can find a by looking at the coefficient of x^2. You can find b by looking at the coefficient of x. You can find c by looking at the constant at the end.

Now use the discriminant formula.

b^2 - 4ac

After plugging in and solving, check the number. If it is negative, there are no real solutions. If it is positive there are 2 solutions. If it is 0, there is one real answer and it is a double root.

attashe74 [19]2 years ago

4 0

If the discriminant(b^2-4ac) is rational, then the quadratic is rational.

~ThePirc

You might be interested in

If a hand sanitizer cleans 99.9% of bacteria if u use it 2 times does that make it 100%

Viktor [21]

Answer:

It's true

Step-by-step explanation:

I hope it helps you

7 0

2 years ago

The dimensions of a 7-cm by 2-cm rectangle are<br> multiplied by 3. How is the area affected?

Soloha48 [4]

Answer:

Original rectangle: Since the area of a rectangle is the length * width, the area of this rectangle is 7 * 2 = 14 square cm.

New rectangle: The new dimensions of this are 7*3 = 21 cm by 2*3 = 6 cm. To find the area, we multiply these two together. 21*6 = 126 square cm.

126 is 9 times greater than 14, so the area will be multiplied by 9.

Step-by-step explanation:

3 0

2 years ago

I need help!

irakobra [83]

Answer:

If a is positive and b is greater than 1 , then it is exponential growth. If a is positive and b is less than 1 but greater than 0 , then it is exponential decay

Step-by-step explanation:

small baby answer

5 0

2 years ago

In a survey of 100 people, 10 preferred onions on their hot dogs. What percent preferred onions?

Aleks [24]

1/10 if you divide 10 by 100 it would be 1/10

4 0

2 years ago

Just Need A Few Questions Answered To Finish My Quiz, Any Help Would Be Much Appreciated.

kvv77 [185]

Given the triangle

PQR

with points

P(8,0)

Q(6,2)

R(-2,-4)

And the triangle

P'Q'R'

with points

P'(4,0)

Q'(3,1)

R'(-1,-2)

Part A. Scale factor

Using the vertex

P( 8, 0)

P'(4,0)

the dilatation factor is given by

$\frac{4}{8}=\frac{1}{2}$

The triangle has a dilatation factor of 1/2

Part B:

P''Q''R'' after using P'Q'R' reflected about the y axis

to make a reflection over the y axis

coordinates (x,y) turn into coordinates (-x,y)

as follows

$P^{\prime}(4,0)\rightarrow P^{\prime\prime}(-4,0)$ $Q^{\prime}(3,1)\rightarrow Q^{\prime\prime}(-3,1)$ $R^{\prime}(-1,-2)\rightarrow R^{\prime\prime}(1,-2)$

Then triangle P''Q''R'' has coordinates

P''(-4,0)

Q''(-3,1)

R''(1,-2)

Part C:

PQR is congruent to P''Q''R''?

Congruent triangles are triangles that have the same size and shape. This means that the corresponding sides are equal and the corresponding angles are equal.

Then the triangles are not congruent

8 0

4 months ago