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kipiarov [429]
3 years ago
15

(V-W)T=a. Solve for V

Mathematics
2 answers:
IRISSAK [1]3 years ago
6 0
V=a+w
The T will be gone because you have to divide it with (v-w).
ex:
TV-TW/T=a
V-W=a
+W +W

answer is V=a+w
jasenka [17]3 years ago
4 0
(V - W)T = a             Use the Distributive Property
VT - WT = a             Add WT to both sides
         VT = a + WT   Divide both sides by T
           V = \frac{a + WT}{T}   Cancel out the \frac{T}{T}
           V = \frac{a}{T} + W
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Black bird starts his flight path from (2, 0). his flight path reaches a maximum height of 20 yards and lands at point (38, 0).
Salsk061 [2.6K]

The maximum height is 20 yards and the total horizontal distance is 36 yards, which is the distance between the point (2, 0) and (38, 0).

<h3>What is a parabola?</h3>

It is defined as the graph of a quadratic function that has something bowl-shaped.

We have:

The blackbird starts his flight path from (2, 0). His flight path reaches a maximum height of 20 yards and lands at point (38, 0).

Here the bird path will be a parabola with a maximum height of 20 yards.

The total horizontal distance traveled by the bird = The distance between the points (2, 0) and (38, 0)

= √(38-2)²

= 36 yards

Thus, the maximum height is 20 yards and the total horizontal distance is 36 yards, which is the distance between the point (2, 0) and (38, 0).

Learn more about the parabola here:

brainly.com/question/8708520

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8 0
2 years ago
Which expression should you simplify to find the 90% confidence interval,
bogdanovich [222]

Answer:

0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.2870.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613

we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

Step-by-step explanation:

The estimated proportion of interest is \hat p=0.45

We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025.

And the critical value is:z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the true population proportion is interest is given by this formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Replacing the values provided we got:

0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287\\\\0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

5 0
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Answer:

m =  \frac{ - 1 - 4}{2  + 3}  \\ m =  - 1

Good luck!

Intelligent Muslim,

From Uzbekistan.

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